All categories

3 years ago

A _ is a substance with a pH greater than 7

Chemistry

1 answer:

Verizon [17]3 years ago

4 0

BASIC

bc here:

1,2,3,4,5,6. 7. 8,9,10

The ones in bold are acids.

7 is neutral.

The ones in italic are basic.

You might be interested in

The periodic law states that the physical and chemical properties of elements are periodic functions of their?

svetoff [14.1K]

The periodic law states that the physical and chemical properties of elements are periodic functions of their "Atomic Numbers"

So, option B is your answer.

Hope this helps!

6 0

3 years ago

The diameter of carbon atom is 0.000000000 154m. What is the number expressed in scientific notation

kogti [31]

1.54×10 −10

one and fifty four-hundreths times ten to the power of negitiive 10

7 0

3 years ago

Read 2 more answers

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

3 years ago

A negative change in entropy indicates that...

vovangra [49]

Answer:

B. the products have a smaller number of available energy microstates than the reactants.

4 0

3 years ago

Read 2 more answers

How many moles of aluminum are needed to make 9 moles of molecular hydrogen? given the reaction: 2 al + 6 hcl → 2 alcl3 + 3h2 6

sergiy2304 [10]

1) Chemical equation

2Al + 6 HCl ---> 2Al Cl3 + 3 H2

2) molar ratios

2 mol Al : 3 moles H2

3) Proportion

2 mol Al / 3mol H2 = x / 9 mol H2

4) Solve for x

x = 9 mol H2 * 2 mol Al / 3 mol H2 = 6 mol Ag

Answer: 6 moles

7 0

3 years ago