Answer:
a. add a little distilled water to see which layer the water adds to
Explanation:
The problem tells us to keep in mind two major aspects of the test: It has to be <em>simple</em>, as well as <em>non-destructive</em>:
- Adding distilled water can be made in under a minute, without requiring specialized laboratory equipment, unlike IR.
- It is also non-destructive, because the contents on either layer won't change due to the added distilled water.
<span>Gallium is used to improve the conductivity of germanium</span>
½H2(g) + ½I2(g) → HI(g) ΔH = +6.2 kcal/mol
or...
½H2(g) + ½I2(g) + 6,2kcal/mole → HI(g)
________
21.0 kcal/mole + C(s) + 2S(s) → CS2(l)
or...
C(s) + 2S(s) → CS2(l) ΔH = +2,1 kcal/mole
_________
ΔH > 0 ----------->>> ENDOTHERMIC REACTIONS
It is a mixture. it can easily be separated.
