We have that
<span>y=2x-1
and
Y=2x+3
the two lines are parallel
because the slopes are the same
m=2
we know that
</span>If two lines are parallel<span>, then they will never intersect
</span><span>
therefore
the answer is the option
</span><span>D no solution</span><span>
</span>
Answer:
53.3 degrees
Step-by-step explanation:
∆DEF and ∆RSQ are similar. We know this, because the ratio of their corresponding sides are equal. That is:
DE corresponds to RS
EF corresponds to SQ
DF corresponds to RQ.
Also <D corresponds to <R, <E corresponds to <S, and <F corresponds to <Q.
The ratio of their corresponding sides = DE/RS = 6/3 = 2
EG/SQ = 8/4 = 2
DF/RQ = 4/2 = 2.
Since the ratio of their corresponding sides are equal, it means ∆DEF and ∆RSQ are similar.
Therefore, their corresponding angles would be equal.
Thus, m<Q = m<F
Let's find angle F
m<F = 180 - (98 + 28.7)
m<F = 53.3°
Since <F corresponds to <Q, therefore,
m<Q = 53.3°
This is just simple Pythagorean’s theorem. a^2 + b^2 = c^2
Number 2:
5^2 + x^2 = 10^2
25 + x^2 = 100
x^2 = 75
x = sqrt 75 = 5*sqrt(3)
Number 3:
4^2 + x^2 = 7^2
16 + x^2 = 49
x^2 = 33
x = sqrt 33
Answer:
Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.
Given: △ABC, m∠B=90°
Find: AC and BK.
Short leg 90 degrees Long leg Hypotenuse
AB=12 90 BC=16 AC= ?
AK = ? 90 BK = ? AB=12
AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]
Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]
BK / 16 = AB / AC
BK / 16 = 12 / 20
BK = (3/5)16
BK = 48/5
another answer let see this
AB^2+BC^2=AC^2
12^2+16^2=AC^2
144+256=AC^2
400=AC^2
20=AC
# be careful#
Answer:
51
Step-by-step explanation:
Hey There!
To find the perimeter of any figure all you have to do is add up all of the side lengths
5+5+7+11+7+16=53
so the perimeter is equal to 51
Note: the 18 is from the bottom length of the figure
you would have to add the 5 and 11
the extra seven is from the very right side length
