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Flauer [41]
3 years ago
14

A scientist cools some water at a constant rate. the graph and table show how the temperature of the water changes with time.

Mathematics
2 answers:
irina1246 [14]3 years ago
6 0

Answer:

C

Step-by-step explanation:

The easiest way to determine this is to realize that time is the independent variable (n) and temperature is the dependent variable (a).

From the table, we can plug in the two points (n) into n of each equation and see if that equals the temperature values (a).

<em>A little thinking would get us to plug the numbers in C first.</em>

<em>a(n)=46-(n-1)*4\\46-(5-1)*4=30</em>

<em>Works!!</em>

<em>Now, second number:</em>

<em>a(n)=46-(n-1)*4\\46-(6-1)*4=26</em>

<em>Works!!</em>

<em />

<em>Hence, C is the correct answer.</em>

drek231 [11]3 years ago
4 0

Answer:

a(n)=46-(n-1) \times 4

Step-by-step explanation:

It's important to know that the graph is showing a linear function, which means its equation cannot be exponential. So, choices A and B are not correct here.

To find the correct equation, we could find the slope first with the following formula and the two given points

m=\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }\\ m=\frac{26-30}{6-5}=4

Now, we use the point-slope formula to find the equation

y-y_{1} =m(x-x_{1} )\\y-30=4(x-5)\\y=4x-20+30\\y=4x+10

Notice that choice C has the same coefficient of 4, which is the slope of the line. Therefore, that's the right answer.

Let's prove it for n=6

a(n)=46-(n-1) \times 4\\a(6)=46-(6-1) \times 4=46-20=26

As the table shows.

Therefore, choice C is correct.

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Answer with Step-by-step explanation:

We are given that

r(t)=< t^2,\frac{2}{3}t^3,t >

We have to find T,N and B at the given point t > (1,2/3,1)

r'(t)=

\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1

T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}

Now, substitute t=1

T(1)=\frac{}{2+1}=\frac{1}{3}

T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}

T'(1)=-\frac{4}{9}+\frac{1}{3}

T'(1)=\frac{1}{9}=

\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}

N(1)=\frac{T'(1)}{\mid T'(1)\mid}

N(1)=\frac{}{\frac{2}{3}}=

N(1)=

B(1)=T(1)\times N(1)

B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}

B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})

B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k

B(1)=\frac{1}{3}

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Are the lines y=3x+10 and y−7=1/3(x+2) parallel, perpendicular, or neither?
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Answer:

Neither

Step-by-step explanation:

The image below shows that the lines aren’t parallel. They instead, intersect, but they are not perpendicular. So it’s neither.

<em>Hope this helps!</em> :)

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3 years ago
How many license plates in Ontario were registered between the following licence plates? As the question is asking for plates be
Liono4ka [1.6K]

The number of plates is an illustration of permutation and combination

The number of plates is 2592

<h3>How to determine the number of plates</h3>

The range is given as: AVVJ 144 To: BVNP 199 (exclusive)

From the range, we have the following highlights:

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The number of plates (n) is then calculated as:

n = 2 * 1 * 24 * 54

Evaluate the product

n = 2592

Hence, the number of plates (n) is 2592

Read more about permutation and combination at:

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Answer:

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∠CDE

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