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____ [38]
3 years ago
11

Is 48,615,453 divisible by 9? 20 pts!

Mathematics
2 answers:
Licemer1 [7]3 years ago
6 0

Answer:

yes 48615453 is divisible by 9.

Zepler [3.9K]3 years ago
3 0
The answer is: 5,401,717
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Solve the equation: 1/6d+2/3=1/4(d-2)
nlexa [21]

d/6+2/3=1/4(d-2)

d/6+2/3=d-2/4

2d+8=3(d-2)

2d+8=3d-6

8=3d-6-2d

8=d-6

8+6=d

14=d

d=14



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Determine whether QRS is a right triangle for the given vertices. Explain.
LekaFEV [45]

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Step-by-step explanation:

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Which measures of central tendency would be affected if the outlier 11 was added to the following set 27,20,34,37,21,42,39
MrRa [10]

Answer:

Median will not be affected by the outlier.

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3 years ago
Determining Whether a Difference Is Statistically
SCORPION-xisa [38]

Using the z-distribution, it is found that:

  • The 95% confidence interval is of -1.38 to 1.38.
  • The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

<h3>What is the z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm zs

In which:

  • \overline{x} is the difference between the population means.
  • s is the standard error.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The estimate and the standard error are given by:

\overline{x} = 0, s = 0.69

Hence the bounds of the interval are given by:

\overline{x} - zs = 0 - 1.96(0.69) = -1.38

\overline{x} + zs = 0 + 1.96(0.69) = 1.38

1.74 is outside the interval, hence:

  • The 95% confidence interval is of -1.38 to 1.38.
  • The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ2

6 0
2 years ago
What is the answer to rounding 12.3
AnnZ [28]
To round it would be 0-4 you keep the same # 5-up so in this case it would be 12 ,
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3 years ago
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