At the Olympic level of competition, even the smallest factors can make the difference between winning and losing. For example,
Pelton (1983) has shown that Olympic marksmen shoot much better if they fire between heartbeats, rather than squeezing the trigger during a heartbeat. The small vibration caused by a heartbeat seems to be sufficient to affect the marksman’s aim. Olympic marksmen fire a series of rounds while a researcher records heartbeats. For each marksman, a score is recorded for shots fired during heartbeats and for shots fired between heartbeats.
Answer the following questions.
1. Focus on the Descriptive Statistics output. Compare the means for the two conditions. Remember that the marksmen were measured twice, when they shot during heartbeats and when they shot between heartbeats. At which time, during or between, did they score more points?
2. Focus on the Paired Samples T-Test output. a. What is the value for t? b. What is p? p is the exact alpha that corresponds to the value for t. c. Should the researcher reject or retain the null hypothesis? d. Note that a paired-samples t-test is the same thing as a repeated- measures t-test.
3. If there’s a difference in shots taken during and between heartbeats, you should expect to see a significant difference between the two conditions. According to the findings reported in the output above, was there a significant difference between the scores for the marksmen during and between heartbeats?
Answer the following questions.
1. Focus on the Descriptive Statistics output. Compare the means for the two conditions. Remember that the marksmen were measured twice, when they shot during heartbeats and when they shot between heartbeats. At which time, during or between, did they score more points?
2. Focus on the Paired Samples T-Test output. a. What is the value for t? b. What is p? p is the exact alpha that corresponds to the value for t. c. Should the researcher reject or retain the null hypothesis? d. Note that a paired-samples t-test is the same thing as a repeated- measures t-test.
3. If there’s a difference in shots taken during and between heartbeats, you should expect to see a significant difference between the two conditions. According to the findings reported in the output above, was there a significant difference between the scores for the marksmen during and between heartbeats?
1 answer:
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Answer:
We conclude that the equivalent expression is:
Step-by-step explanation:
Given the expression
Remove parentheses: (a) = a
Multiply the numbers: 3 × 2 = 6
Multiply the numbers: 4 × 5 = 20
Multiply the numbers: 4 × 2 = 8
Thus, we conclude that the equivalent expression is:
Answer and Step-by-step explanation:
In the equation y = 25x + 100, the format of y = mx + b is being used. This is a very commonly used base for equations in math, especially when it comes to graphing.
In the equation, the m stands for the slope in the equation, and the b stands for the y intercept. Slope can also be found by taking the rise/run of a graph.
So, the slope of this line is 25, and the y-intercept 100.
I have also included the this equation on a graph as well.
I hope that this helps.
Answer:
a) The mean number is 745 and the standard deviation is 25.18.
b) 896 deaths is a significantly high number, which means that there is cause for concern.
Step-by-step explanation:
For each death, there are only two possible outcomes. Either it is attributable to myocardial infarctions, or it is not. The probability of a death being attributable to myocardial infarctions is independent of other deaths. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
A value X is significantly high is:
In this problem:
a. Find the mean and standard deviation for the number of such deaths that will occur in typical region with 5000 deaths.
The mean number is 745 and the standard deviation is 25.18.
b. In one region, 5000 death certificates are examined, and it is found that 896 deaths were attributable to myocardial infarction. Is there cause for concern? Why or why not?
Is 896 a significantly high number?
895 > 795.36
896 deaths is a significantly high number, which means that there is cause for concern.