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3 years ago

Describe how temperature affects the rate of a reaction

1 answer:

8 0

Hello! The reactions are catalyzed, or sped up by enzymes. Enzymes have strict conditions they can work under, including a small range of temperature. Temperature increase slows the rate of reaction, and extreme temperature increase can denature, or destroy an enzyme. Hope this helps! :)

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How can atoms have more than 32 electons?

guajiro [1.7K]

86 atoms have more electrons than Germanium

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2 years ago

What is a molecular formula?

polet [3.4K]

The symbolic representation of its compound and its composition.

or a chemical formula that indicates the kinds of atoms and the number of each kind in a molecule of a compound.
ANSWER IS B

5 0

2 years ago

Answer choices are A. Constant speed<br> B. Stopped<br> C.Moving sideways<br> D.Accelerating

Maurinko [17]

B.stopped
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2 years ago

15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams

sveticcg [70]

Answer:

$\boxed {\tt A. \ d=0.85 \ g/mL}$

Explanation:

Density is found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

$m= 12.7 \ g\\v= 15 \ mL$

Substitute the values into the formula.

$d=\frac{12.7 \ g}{ 15 mL}$

Divide.

$d=0.846666667 \ g/mL$

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

$d \approx 0.85 \ g/mL$

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

4 0

2 years ago

What is the pressure of 1.20 moles of SO2 gas in a 4L container at 30 degrees celsius

geniusboy [140]

Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

P V = n R T
Solving for P,
P = n R T / V ----- (1)
Data Given;

Moles = n = 1.20 mol

Volume = V = 4 L

Temperature = T = 30 + 273 = 303 K

Gas Constant = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

P = (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

P = 7.45 atm

6 0

2 years ago

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