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klasskru [66]
2 years ago
13

Zinc, sulphur, oxygen What would this compound be called?

Chemistry
1 answer:
Nataliya [291]2 years ago
6 0

Zinc sulphate

Zinc sulphateZnSO₄

This is the answer.

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As the sun heats the surface of the ocean, two layers of water result. What separates the layers.
pychu [463]

Question:<u> As the sun heats the surface of the ocean, two layers of water result. What separates the layers.?</u>

Answer: <u>The Thermocline </u>

<em>Hope this helps!.</em>

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<em>~A.W~ZoomZoom44</em>

4 0
3 years ago
How many atoms of carbon are in a container that has 0.450 mol of CO2 and 2.55 mol of CaC2?
Fantom [35]

Answer:

The number of carbon atoms in the container is 1.806 × 10²⁴ or the container contains 1.806 × 10²⁴ atoms of carbon

Explanation:

By Avogadro's number, 1 mole of a substance contains 6.02 × 10²³ particles of the substance

Here we have 0.45 mole of CO₂ contains

0.45 × 6.02 × 10²³ particles of CO₂ that is 2.709 × 10²³ particles of CO₂ or equivalent to 2.709 × 10²³ atoms of Carbon

Similarly, 2.55 moles of CaC₂ contains 2.55 × 6.02 × 10²³ particles of CaC₂ or 1.5351 × 10²⁴ atoms of Carbon

The total number of carbon atoms is therefore;

2.709 × 10²³ + 1.5351 × 10²⁴ = 1.806 × 10²⁴ atoms of carbon.

5 0
3 years ago
What is ph of a solution that contains 1.32 grams of nitric acid hno3 dissolved in 750 ml of water​
Agata [3.3K]

what is the pOH of the solution? 10.25 is the answer

3 0
3 years ago
Write the name of any two metalloids ?​
sertanlavr [38]

Answer:

Germanium and Polonium

Explanation:

Can you please mark me brainliest since I was the first person to answer :p

4 0
3 years ago
Read 2 more answers
What is the theoretical yield of aluminum oxide if 1.40 mol of aluminum metal is exposed to 1.35 mol of oxygen?
jasenka [17]

Answer:

71.372 g or 0.7 moles

Explanation:

We are given;

  • Moles of Aluminium is 1.40 mol
  • Moles of Oxygen 1.35 mol

We are required to determine the theoretical yield of Aluminium oxide

The equation for the reaction between Aluminium and Oxygen is given by;

4Al(s) + 3O₂(g) → 2Al₂O₃(s)

From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.

Therefore;

1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen

1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium

Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.

4 moles of aluminium reacts to generate 2 moles aluminium oxide.

Therefore;

Mole ratio Al : Al₂O₃ is 4 : 2

Thus;

Moles of Al₂O₃ = Moles of Al × 0.5

                         = 1.4 moles × 0.5

                         = 0.7 moles

But; 1 mole of Al₂O₃ = 101.96 g/mol

Thus;

Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol

                                            = 71.372 g

3 0
3 years ago
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