<u>Answer:</u> 6.57 L of solution can be made.
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
Given values:
Molarity of LiBr = 3.5 M
Moles of LiBr = 23 moles
Putting values in equation 1, we get:
![3.5mol/L=\frac{23mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{23mol}{3.5mol/L}=6.57L](https://tex.z-dn.net/?f=3.5mol%2FL%3D%5Cfrac%7B23mol%7D%7B%5Ctext%7BVolume%20of%20solution%7D%7D%5C%5C%5C%5C%5Ctext%7BVolume%20of%20solution%7D%3D%5Cfrac%7B23mol%7D%7B3.5mol%2FL%7D%3D6.57L)
Hence, 6.57 L of solution can be made.
Cc stands for cm cubed (cubic centimetre).
So
6cc=6 cm^3.
We are given with
136 g P4
excess oxygen
The complete combustion reaction is
P4 + 5O2 => 2P2O5
Converting the amount of P4 to moles
136/123.9 = 1.098 moles
Using stoichiometry
moles P2O5 = 1.098 x 2 = 2.195 moles P2O5
the sugar disolved into the water so its a <u>mixture</u>. boom those words are it
Answer:
![V_2=146mL](https://tex.z-dn.net/?f=V_2%3D146mL)
Explanation:
Hello there!
In this case, since the equation for the calculation of dilutions is:
![M_1V_1=M_2V_2](https://tex.z-dn.net/?f=M_1V_1%3DM_2V_2)
Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:
![V_2=\frac{M_1V_1}{M_2}=\frac{0.885M*82.5mL}{0.500M}\\\\V_2=146mL](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BM_1V_1%7D%7BM_2%7D%3D%5Cfrac%7B0.885M%2A82.5mL%7D%7B0.500M%7D%5C%5C%5C%5CV_2%3D146mL)
Best regards!