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fgiga [73]
2 years ago
9

Which cells have only one copy of each chromosome? diploid haploid homologous zygote

Biology
1 answer:
Veseljchak [2.6K]2 years ago
6 0
Ehshdbcbdnjdhfhdbcsvdvshdvdhjfkd
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O que é teoria panspermia?​
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Answer:

Las teorías extraterrestres o de panspermia sugieren que la vida existió en el espacio exterior y fue transportada por meteoritos, asteroides o cometas a una Tierra receptiva. En este caso, el origen de la vida no está relacionado con los posibles entornos de la Tierra primitiva.

Explanation:

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True or False <br> Evolution leads to diversity of life.
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the answer is true

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n the 1950’s, Anfinsen carried out denaturation and renaturation experiments of the protein RNAse (ribonuclease) in vitro. After
beks73 [17]

Answer and Explanation:

The regular synthetic denaturant of proteins is urea. The high grouping of urea causes unfolding of protein and accordingly brings about loss of capacity of protein. The urea communicates with the protein and counteracts collapsing of protein.

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The difference in physical and chemical properties of protein after oxidation and in nearness of urea can't be altered even after expulsion of urea. Along these lines, protein doesn't crease appropriately.

5 0
3 years ago
Consider a locus with two alleles - B and b. B is dominant, while b is recessive. There is no mutation. B has a selective advant
Marat540 [252]

Answer:

0.09

Explanation:

<h3><u>Before selection</u></h3>

Total number in population = 1000

Genotype frequencies

Genotype frequency of BB = 500/1000 = 0.5

Genotype frequency of Bb = 250/1000 = 0.25

Genotype frequency of bb = 250/1000 = 0.25

Allele frequencies

Allele frequency of B = BB genotype frequency + half of the Bb genotype frequency = 0.5 + (0.25/2) = 0.625

Allele frequency of b = bb genotype frequency + half of the Bb genotype frequency = 0.25 + (0.25/2) = 0.375

<h3><u>After selection</u></h3>

We are told that after selection, the genotype frequency of bb is changed as they become 50% less fit. This means the frequency of bb individuals changes from 250 to 125 individuals (50% reduction).

Now the total number of individuals is 500 + 125 + 250 = 875.

Genotype frequencies

Genotype frequency of BB = 500/875 = 0.57

Genotype frequency of Bb = 250/875 = 0.29

Genotype frequency of bb = 125/875 = 0.14

Allele frequencies

Allele frequency of B = BB genotype frequency + half of the Bb genotype frequency = 0.57 + (0.29/2) = 0.715

Allele frequency of b = bb genotype frequency + half of the Bb genotype frequency = 0.14 + (0.29/2) = 0.285

<h3><u>Change in frequency of B after 1 generation</u></h3>

0.715 - 0.625 = 0.09

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3 years ago
Any environmental resource that, because it is scarce or at unfavorable levels, restricts the ecological niche of an organism is
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