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Reptile [31]
2 years ago
5

Lawerence kohl berg developed the theory of

Physics
1 answer:
Natali [406]2 years ago
7 0

Explanation:

Kohlberg's theory of moral development is a theory that focuses on how children develop morality and moral reasoning. Kohlberg's theory suggests that moral development occurs in a series of six stages. The theory also suggests that moral logic is primarily focused on seeking and maintaining justice.

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. Mike Powell holds the record for the long jump of 8.95 m, established in 1991. If he left the ground at an angle of 15°, what
nadezda [96]

Answer:

13.3 m/s

Explanation:

The motion is a projectile motion. The horizontal distance travelled, called the range, is given by

R = \dfrac{u^2\sin2\theta}{g}

u is the initial speed, \theta is the angle with the horizontal and g is acceleration of gravity.

u = \sqrt{\dfrac{Rg}{\sin2\theta}}= \sqrt{\dfrac{8.95\times9.81}{\sin30^\circ}}=13.3 \text{ m/s}

6 0
3 years ago
HELP PLEASE I NEED THE ANSWERS FAST (15 POINTS)
ahrayia [7]

Answer: 1) Cold water is more dense and will sink in room temperature water.

2) Cold salty water is denser than warm freshwater.

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4) Salinity and density share a positive relationship. As density increases, the amount of salt in water-also known as salinity- increases.

5 0
3 years ago
Average distance of 160.0 cm. Its average time was 5.74 seconds. What is its average speed?
Gre4nikov [31]
Your answer is .279m/s
5 0
3 years ago
In a simple electric circuit, Ohm's law states that V=IRV=IR, where V is the voltage in volts, I is the current in amperes, and
VMariaS [17]

To solve this problem, apply the concepts given from Ohm's Law. From there we will obtain the derivative of the function with respect to time and with the previously given values we will proceed to find the change in current as a function of the derivative

V = IR

Here

I = Current

V = Voltage

R = Resistance

Taking the derivative we will have,

\frac{dV}{dt} = \frac{dI}{dt}R + I \frac{dR}{dt}

Our values are given as,

\frac{dV}{dt} = -0.01

\frac{dR}{dt} = 0.04\Omega/s

R = 300\Omega

I = 0.01A

Replacing we will have that

\frac{dV}{dt} = \frac{dI}{dt}R + I \frac{dR}{dt}

-0.01 = \frac{dI}{dt}(300\Omega) + (0.01A)(0.04\Omega/s)

Rearranging to find the current through the time,

\frac{dI}{dt} = \frac{-0.01- (0.01A)(0.04\Omega/s)}{(400\Omega)}

\frac{dI}{dt} = -0.000026A/s

Therefore the change of the current is -0.000026A per second

3 0
3 years ago
Help plzzz ASAP thanks
maria [59]

Answer:

40J

Explanation:

8 0
4 years ago
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