Answer:
Ring v² = gh
solid wheel (cylinder) v² = 4/3 gh
Explanation:
Let's use conservation of energy to find the speed of the wheels at the bottom of the hill.
starting point. Point before starting movement
Em₀ = mgh
final point. At the bottom of the hill
Em_f = K = ½ m v² + ½ I w²
energy is conserved
Emo = Em_f
mgh = ½ m v² + ½ I w²
angular and linear velocity are related
v = w r
we substitute
mgh = ½ m v² + ½ I v² / r²
mgh = 
½ (m + I / r²) v²
v² = 
the moments of inertia are tabulated
Ring
I = mr²
v² = 2 m g h / (m + m)
v² = gh
solid wheel (cylinder)
I = ½ m r²
v² = 2m gh / (m + m / 2)
v² = 4/3 gh
We can see that due to the difference in the moment of inertia of each body it is different, the solid wheel has more speed when it reaches the lower part of the ramp
The teacher measured the maximum height and the minimum height of ...
5 days ago — ... screen as the wave passed . The teacher repeated his measurements. Table 4 shows the teacher's measurements. Calculate the mean amplitude of the water wave.
Temperature. X-axis is always the independent variable.
Answer:
2874.33 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Now H-h = 0.588 - 0.002 = 0.586 m
The final velocity will be the initial velocity
Acceleration of the frog is 2874.33 m/s²
<span>Density can be determined by the
mass of an object and how much it takes up space (volume). It is represented by
the formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the mass
in kg or lb and V is the volume in m^3 or ft^3. The answer would be A. For example, you are given the mass of an
object of 40.5kg and a volume of 15m^3. Find its density.</span>
D = M/V
D = (40.5 kg)
/ (15 m^3)
<span>D = 27/10 or
2.7 kg/m^3 </span>
