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kondaur [170]
2 years ago
10

Two forces act on wooden box with mass of (30kg) (if F1,=85.7N east and F270.7N west):

Physics
1 answer:
tresset_1 [31]2 years ago
7 0

The acceleration of the wooden box is 6.17 m/s² towards the west.

<h3 /><h3>What is acceleration?</h3>

Acceleration can be defined as the rate of change of velocity.

To calculate the acceleration of the wooden box can be calculated using the formula below.

Formula:

  • F₂-F₁ = ma.................. Equation 1

Where:

  • F₂ = Force on the wooden box acting towards west
  • F₁ = Force on the wooden box acting towards the east
  • m = Mass of the wooden box.
  • a = Acceleration of the wooden box

Make a the subject of the equation

  • a = (F₂-F₁)/m........................ Equation 2

From the question,

Given:

  • F₂ = 270.7 N
  • F₁ = 85.7 N
  • m = 30 kg

Substitute these values into equation 2

  • a = (270.7-85.7)/30
  • a = 185/30
  • a = 6.17 m/s² towards the west.

Hence, The acceleration of the wooden box is 6.17 m/s² towards the west.

Learn more about acceleration here: brainly.com/question/605631


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As the number of turns can not be in decimal so number of turns will be 7

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The two blocks in oscillate on a frictionless surface with a period of 1.5 s. The upper block just begins to slip when the ampli
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0.72

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Maximum acceleration of the block is given as

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frictional force is given as

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As per newton's second law

f = ma \\\\\mu mg = ma \\\mu g = a\\\mu g = Aw^{2}\\\mu (9.8) = (0.40)(4.2)^{2}\\\mu = 0.72

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A machine part has the shape of a solid uniform sphere of mass 250 g and a diameter of 4.30 cm. It is spinning about a frictionl
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Answer:\alpha =9.302\ rad/s^2

Explanation:

Given

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friction will provide resisting torque so

f\times r=I\times \alpha

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\alpha =\text{angular acceleration}

I=\frac{2}{5}mr^2

0.02\times r=\frac{2}{5}mr^2\times \alpha

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t=\dfrac{\Delta \omega }{\alpha }

t=\dfrac{21}{9.302}

t=2.25\ s

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