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kondaur [170]
2 years ago
10

Two forces act on wooden box with mass of (30kg) (if F1,=85.7N east and F270.7N west):

Physics
1 answer:
tresset_1 [31]2 years ago
7 0

The acceleration of the wooden box is 6.17 m/s² towards the west.

<h3 /><h3>What is acceleration?</h3>

Acceleration can be defined as the rate of change of velocity.

To calculate the acceleration of the wooden box can be calculated using the formula below.

Formula:

  • F₂-F₁ = ma.................. Equation 1

Where:

  • F₂ = Force on the wooden box acting towards west
  • F₁ = Force on the wooden box acting towards the east
  • m = Mass of the wooden box.
  • a = Acceleration of the wooden box

Make a the subject of the equation

  • a = (F₂-F₁)/m........................ Equation 2

From the question,

Given:

  • F₂ = 270.7 N
  • F₁ = 85.7 N
  • m = 30 kg

Substitute these values into equation 2

  • a = (270.7-85.7)/30
  • a = 185/30
  • a = 6.17 m/s² towards the west.

Hence, The acceleration of the wooden box is 6.17 m/s² towards the west.

Learn more about acceleration here: brainly.com/question/605631


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Answer:

23 cm

Explanation:

The formula for magnification is;

Magnification = image distance / object distance

use values as;

3.2 = v / 30   where v is image distance

v =30*3.2

v=96 cm

The relationship of the focal length with image distance and object distance is expressed as;

\frac{1}{u} +\frac{1}{v} =\frac{1}{f}

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use values in the equation as;

\frac{1}{30} +\frac{1}{96 }  =\frac{1}{f}

\frac{1}{f} =\frac{7}{160}

f=160/7

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Explanation:

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The energy needed is calculated as follows;

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As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\  M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg

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