Answer:
(a) 4.38 s.
(b) 1.817 s
Explanation:
(a)
Using
θ = ω₀t +1/2αt² ................ Equation 1
Where θ = number of revolution, t = time, α = angular acceleration, ω₀ = angular velocity.
Given: θ = 1.59 rev = 1.59×2π = 9.992 rad, ω₀ = 0 rad/s, α = 1.04 rad/s².
Substitute into equation 1
9.992 = 0(t) + 1/2(1.04)(t²)
t² = (2×9.992)/1.04
t² = 19.984/1.04
t = √(19.215)
t =4.38 s.
(b)
also using
θ = ω₀t +1/2αt²............... Equation 1
Given: θ =3.18 rev = 3.18×2π = 19.97 rad, ω₀ = 0 rad/s, α = 1.04 rad/s².
Substitute into equation 1
19.97 = 0(t) + 1/2(1.04)(t²)
t² = 19.97×2/1.04
t = √(38.40)
t = 6.197 s
The time require = 6.197-4.38 = 1.817 s
