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melamori03 [73]
3 years ago
8

Scientific way of thinking

Physics
2 answers:
Sholpan [36]3 years ago
8 0
What about it, explain more
noname [10]3 years ago
7 0

Answer:

huh,? can you explain the question more please

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Explain the relationships between gravity, mass, and distance. please write a paragraph
Gelneren [198K]
Gravity is an attractive force which every object with mass exerts. The "relationship" tells us how much gravity is exerted between two objects. The formula is F  g =  \frac{G M_1 M_2}{D^2}. what this says is that in order to figure out Fg(Force of gravity), we must take into account G( gravitational constant 6.67x10^-11) x M1(mass 1) x M2(mass2) / d^2(ditance squared). Mass is measured in Kg(kilograms). G never changes,and Fg is in Newtons. In terms of planets, you must take into account the radius of the planet within your distance. In Layman terms, You use all three to figure out how much gravity one object exerts on another and vice versa.
4 0
3 years ago
A single slit of width 0.50 mm is illuminated with light of wavelength 500 nm, and a screen is placed 120 cm in front of the sli
Vaselesa [24]

Answer:

a) 2.4 mm

b) 1.2 mm

c) 1.2 mm

Explanation:

To find the widths of the maxima you use the diffraction condition for destructive interference, given by the following formula:

m\lambda=asin\theta

a: width of the slit

λ: wavelength

m: order of the minimum

for little angles you have:

y=\frac{m\lambda D}{a}

y: height of the mth minimum

a) the width of the central maximum is 2*y for m=1:

w=2y_1=2\frac{1(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}=2.4*10^{-3}m=2.4mm

b) the width of first maximum is y2-y1:

w=y_2-y_1=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[2-1]=1.2mm

c) and for the second maximum:

w=y_3-y_2=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[3-2]=1.2mm

4 0
3 years ago
Calculate the mass of the earth if the radius of the earth is 6.38 × 10^6​
Delicious77 [7]

Answer:

C

Explanation:

C is i thing

7 0
3 years ago
Helppppp!!<br> can a current run through a metal conductor can create a magnetic field
sineoko [7]

Answer:

yesssssssssssssssssss

7 0
3 years ago
A ball moving with an initial velocity of 5 m/s comes to rest after 2s. What was the ball's acceleration?
Inga [223]

Answer:

-2.5m/s²

Explanation:

The acceleration of a body is giving by the rate of change of the body's velocity. It is given by

a = Δv / t        ----------------(i)

Where;

a = acceleration (measured in m/s²)

Δv = change in velocity = final velocity - initial velocity   (measure in m/s)

t = time taken for the change (measured in seconds(s))

From the question;

i. initial velocity = 5m/s

final velocity = 0 [since the body (ball) comes to rest]

Δv = 0 - 5 = -5m/s

ii. time taken = t = 2s

<em>Substitute these values into equation (i) as follows;</em>

a = (-5m/s) / (2s)

a = -2.5m/s²

Therefore, the acceleration of the ball is -2.5m/s²

NB: The negative sign shows that the ball was actually decelerating.

6 0
3 years ago
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