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Arisa [49]
3 years ago
11

5

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0

Answer: to find the mean add up all the scores and then divide it by the number of scores that are there and to find the mode order the numbers lowest to highest and see which number appears the most

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A college parking lot is 140 ft long and 90 ft wide. The college wants to increase the area of the lot by 29% by adding strips o
Novay_Z [31]
The initial dimenssions of the park lot are:

length: 140 ft
width: 90 ft

initial area: 140 * 90 = 12,600 ft^2

Area increased 29% = 12,600 * 1.29 = 16,254 ft^2

width of the strips: x

New length: 140 + x

New width: 90 + x

New area: (140+x)(90+x) = 16,254

Solution of the equation:

12600 + 230x + x^2 = 16254

=> x^2 + 230x - 3654 = 0

Use the quadratic formula.

x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =

x = 14.92

The other solution is negative so it is discarded.

Answer: 15 ft


 
5 0
4 years ago
A party of 5 wants to tip 20% of their total $175 bill. If divided evenly, how much should each person tip?
Mashcka [7]
20% of $175 is $35. Divided between 5 people (35/5=7) would be 7. So each person should tip $7.
6 0
4 years ago
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The histogram represents a data distribution with uniform class widths 1.
aliina [53]
I think it’s b... I don’t but i tried if it is wrong I’m sorry if it was right your welcome
4 0
3 years ago
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Please help me literally need this to be answered in 2 hours P-L-E-A-S-E !!
Sonja [21]

Answer:

Yeah with that type of problem

Step-by-step explanation:

You aint getting answered for the next 4 hours <3

6 0
3 years ago
Ryan has $3$ red lava lamps and $3$ blue lava lamps. He arranges them in a row on a shelf randomly, then turns $3$ random lamps
hjlf

There are 6! = 720 ways of arranging the lamps.

If the leftmost lamp is red, there are 3 choices of lamp in the leftmost position, and the remaining 5 can be placed in any order, so there are 3×5! = 360 ways of arranging the lamps and the leftmost is red.

Hence there is a 360/720 = 1/2 probability that the leftmost lamp is red.

Ignoring lamp color for the moment, the probability of arranging 3 lit lamps and 3 unlit lamps is the same, 1/2.

Since Ryan arranges the lamps randomly by color, then turns 3 of them on randomly, the two events are independent. So

P(leftmost red AND leftmost lit) = P(red) × P(lit) = 1/2² = 1/4

7 0
2 years ago
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