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babunello [35]
3 years ago
6

Figure ABCD is transformed to figure A prime B prime C prime D prime, as shown: A coordinate grid is shown from negative 5 to 0

to 5 on both x -and y-axes. A polygon ABCD has A at ordered pair 1, 3, B at ordered pair 3, 4, C at ordered pair 2, 1, D at ordered pair 1, 1. A polygon A prime B prime C prime D prime has A prime at ordered pair negative 3, 3, B prime at ordered pair negative 5, 4, C prime at ordered pair negative 4, 1, D prime at ordered pair negative 3, 1. Which of the following sequences of transformations is used to obtain figure A prime B prime C prime D prime from figure ABCD? (1 point) Reflection about the x-axis followed by a translation to the right by 2 units Reflection about the y-axis followed by a translation to the left by 2 units Counterclockwise rotation by 90 degrees about the origin followed by a translation to the right by 2 units Counterclockwise rotation by 90 degrees about the origin followed by a translation to the left by 2 units
Mathematics
1 answer:
Bess [88]3 years ago
7 0

Answer:

i need this answer too

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Is one side of a rectangular fish tank best represented by a point, line, plane, or ray?
Inessa05 [86]
<span>One side of a rectangular fish tank can be best represented by a plane because it is two dimensional.Whereas,point,line or a ray are all one dimensional and hence they cannot represent a rectangle as it has two dimensions.</span>
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Read 2 more answers
A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers
icang [17]

Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}

\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}

8 0
3 years ago
Help this is due in a few minutes!!
zloy xaker [14]
I think it’s a im not that sure though
7 0
3 years ago
Does this relation represent a function why or why not?
Serga [27]

Answer:

This is a function and it's because there's only one input for every output.

Step-by-step explanation:

Note: Although 5 and 1 both point to the same number this doesn't take away the validity of the function. :)

5 0
2 years ago
What is the value of the function at x=−2?
Elza [17]

The value of the function is the Y value where the line crosses the given X value.

When X is at -2, the line is on Y = 3


The answer would be y =3

3 0
3 years ago
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