Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then
( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165
For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
8.
48/6 = 8. hope this helps :)
2x^(3)y+7xy-3x^(2)-12y
is in standard form
Answer:
can you tell me more details?
Step-by-step explanation:
