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3 years ago

Which property is illurstaed by this problem. (6.3x)y=6.3(xy)

Mathematics

1 answer:

Sergio [31]3 years ago

6 0

Its the identity property

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If <img src="https://tex.z-dn.net/?f=x-12%5Csqrt%7Bx%7D%20%2B36%3D0" id="TexFormula1" title="x-12\sqrt{x} +36=0" alt="x-12\sqrt{

Elis [28]

Answer:

x = 36

Step-by-step explanation:

$x - 12\sqrt{x} + 36 = 0$

Subtract x and 36 from both sides.

$-12\sqrt{x} = -x - 36$

Divide both sides by -1.

$12\sqrt{x} = x + 36$

Square both sides.

$144x = x^2 + 72x + 1296$

Subtract 144x from both sides.

$0 = x^2 - 72x + 1296$

Factor the right side.

$0 = (x - 36)^2$

$x - 36 = 0$

$x = 36$

Since the solution of the equation involved squaring both sides, we musty check the answer for possible extraneous solutions.

Check x = 36:

$x - 12\sqrt{x} + 36 = 0$

$36 - 12\sqrt{36} + 36 = 0$

$36 - 12\times 6 + 36 = 0$

$36 - 72 + 36 = 0$

$0 = 0$

Since 0 = 0 is a true statement, the solution x = 36 is a valid solution.

6 0

3 years ago

PLEASE HELP IT IS 3:30 AM

Nataly_w [17]

Answer:

The answer is y = -1/3x + 5 !

Step-by-step explanation:

If you observe the line, the y-intercept is 5, from the point in the graph (0,5). From that point, we can see that the rise over run is -1/3. Thus, y = -1/3x + 5.

8 0

3 years ago

The area of the triangle is 28.7 square centimeters. What is the base length of the triangle in centimeters?

Montano1993 [528]

In order to derive the base of a triangle from its area, you need its height as well.

In fact, if we solve the area formula for the base, we have

$A=\dfrac{bh}{2} \iff 2A = bh \iff b=\dfrac{2a}{h}$

So, the base length would be

$b=\dfrac{2\cdot 28.7}{h} = \dfrac{57.4}{h}$

where h is the height relative to the base you're interested in.

3 0

3 years ago

HURRY PLZ Graph a line that passes through the coordinates and tell me the answer plzzz

viva [34]

Answer:

I used the graph shown below.

Step-by-step explanation:

The equation of the line is y = x - 4

6 0

3 years ago

10) Find the measure of angle D. Hint: you must do two math problems to solve

NISA [10]

Answer:

Option A.) 43°

Step-by-step explanation:

Part 10)

step 1

Find the length of side EG

see the attached figure to better understand the problem

we know that

In the right triangle EGF

$cos(65^o)=\frac{EG}{EF}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(65^o)=\frac{EG}{11}$

solve for EG

$EG=(11)cos(65^o)\\EG=4.65\ cm$

step 2

Find the measure of angle D

In the right triangle DEG

$tan(D)=\frac{EG}{DG}$ ----> by TOA (opposite side divided by adjacent side)

substitute the given values

$tan(D)=\frac{4.65}{5}\\\\D=tan^{-1}(\frac{4.65}{5})=43^o$

3 0

3 years ago