Answer:
It can do all the functions at a speedy rate and also helps us to search and progress in our homes and businesses. A computer can therefore be called a calculator with a twist for not only does it perform fast calculations, but it also has other special characteristics.
Explanation:
hope it helps you
Answer:
suppose i was i would tell them i dont know and walk away
Explanation:
in thoery this is correct
you said suppose so i answerd
there is no use in reporting or getting this taken down
nether is it right
im not stealing points
Because in thoery its an answer
<em><u>THIS IS MY PROTEST</u></em>
Answer:
The correct word for the blank space is: baseline standards.
Explanation:
Minimum Baseline Standards (MBS) refers to the minimum security guidelines companies set to protect their sensitive data. To achieve such objective, all the devices of an entity -<em>e.g.: servers, routers, and firewalls</em>- must be configured in a form that prevents external or internal attacks. Setting an MBS helps an organization to provide technical support faster since regular users will be working with a system that was implemented by the <em>Information Technology</em> (IT) department of the same association.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
