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balu736 [363]
3 years ago
8

All rear seats in hatchback vehicle models fold down in a "split"

Engineering
1 answer:
Goryan [66]3 years ago
4 0

Answer:

ueusjw9wjqijwdnfuifjrkwjfnd

You might be interested in
The transfer function of a typical tape-drive system is given by
maw [93]

Answer:

the range of K can be said to be :  -3.59 < K< 0.35

Explanation:

The transfer function of a typical tape-drive system is given by;

KG(s) = \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]}

calculating the characteristics equation; we have:

1 + KG(s) = 0

1+   \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]} = 0

{s[s+0.5)(s+1)(s^2+0.4s+4)]} +{K(s+4)}= 0

s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ 2s+K(s+4) = 0

s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ (2+K)s+ 4K = 0

We can compute a Simulation Table for the Routh–Hurwitz stability criterion Table as  follows:

S^5             1                     5.1                          2+ K

S^4            1.9                   6.2                           4K

S^3             1.83            \dfrac{1.9 (2+K)-4K}{1.9}          0

S^2        \dfrac{11.34-1.9(X)}{1.83}       4K                         0

S          \dfrac{XY-7.32 \ K}{Y}        0                            0

\dfrac{1.9 (2+K)-4K}{1.9} = X

 

\dfrac{11.34-1.9(X)}{1.83}= Y

We need to understand that in a given stable system; all the elements in the first column is usually greater than zero

So;

11.34  - 1.9(X) > 0

11.34  - 1.9(\dfrac{3.8+1.9K-4K}{1.9}) > 0

11.34  - (3.8 - 2.1K)>0

7.54 +2.1 K > 0

2.1 K > - 7.54

K > - 7.54/2.1

K > - 3.59

Also

4K >0

K > 0/4

K > 0

Similarly;

XY - 7.32 K > 0

(\dfrac{3.8+1.9K-4K}{1.9})[11.34  - 1.9(\dfrac{3.8+1.9K-4K}{1.83}) > 7.32 \ K]

0.54(2.1K+7.54)>7.32 K

11.45 K < 4.07

K < 4.07/11.45

K < 0.35

Thus the range of K can be said to be :  -3.59 < K< 0.35

4 0
3 years ago
2- A 2-m3 insulated tank containing ammonia at -20 C, 80% quality, is connected by a valve to a line flowing ammonia at 2 MPa, 6
alekssr [168]

Answer:

The valve should be closed at 1081 kPa ⇒ 11 bar

Explanation:

Q_{C_V} + m_ih_i = m_2u_2 - m_1u_1 + W_{C_V}

Q_{C_V} = W_{C_V} = 0

m_1 = \frac{V}{v_1}  = \frac{2}{0.49927} = 4.006 kg

m_i = m_2 - m_1 = 15 - 4.006 = 10.994 kg

u_1 = 1057.5, h_i = 1509.9

u_2 =  m_ih_i + m_1u_1

m_2 = \frac{[10.994*1509.9] + [4.006*1057.5]}{15}  = 1389.1 kJ/kg

v_2 = \frac{V}{m_2} = \frac{2}{15} = 0.1333 m^3/kg

Therefore, v₂, u₂ fix state 2.  

​By trial and error, P₂ = 1081 kPa & T₂ = 50.4° C

1081 kPa ⇒ 11 bar

8 0
4 years ago
A. Imagine the white car in the left lane is moving more slowly than the surrounding traffic. How is this a violation of a state
asambeis [7]

The roads have pre-described lanes that should follow a particular speed and rules. When a driver drives slowly than he makes the other drivers impatient.

<h3>What are traffic rules?</h3>

Traffic rules are the regulations that are defined to regulate the vehicles and other conveyances that walk on the road. They are different in various places and have separate punishments for not following them.

The left lane of the road is generally for the drivers who want to pass by the vehicle ahead by following the mph rule. If the driver drives slowly then they make the other people impatient and result in honking.

Therefore, the driver driving slowly in the left lane makes others impatient.

Learn more about traffic rules here:

brainly.com/question/6034089

#SPJ2

4 0
2 years ago
Read 2 more answers
Please answer fast. With full step by step solution.​
lina2011 [118]

Let <em>f(z)</em> = (4<em>z </em>² + 2<em>z</em>) / (2<em>z </em>² - 3<em>z</em> + 1).

First, carry out the division:

<em>f(z)</em> = 2 + (8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1)

Observe that

2<em>z </em>² - 3<em>z</em> + 1 = (2<em>z</em> - 1) (<em>z</em> - 1)

so you can separate the rational part of <em>f(z)</em> into partial fractions. We have

(8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1) = <em>a</em> / (2<em>z</em> - 1) + <em>b</em> / (<em>z</em> - 1)

8<em>z</em> - 2 = <em>a</em> (<em>z</em> - 1) + <em>b</em> (2<em>z</em> - 1)

8<em>z</em> - 2 = (<em>a</em> + 2<em>b</em>) <em>z</em> - (<em>a</em> + <em>b</em>)

so that <em>a</em> + 2<em>b</em> = 8 and <em>a</em> + <em>b</em> = 2, yielding <em>a</em> = -4 and <em>b</em> = 6.

So we have

<em>f(z)</em> = 2 - 4 / (2<em>z</em> - 1) + 6 / (<em>z</em> - 1)

or

<em>f(z)</em> = 2 - (2/<em>z</em>) (1 / (1 - 1/(2<em>z</em>))) + (6/<em>z</em>) (1 / (1 - 1/<em>z</em>))

Recall that for |<em>z</em>| < 1, we have

\displaystyle\frac1{1-z}=\sum_{n=0}^\infty z^n

Replace <em>z</em> with 1/<em>z</em> to get

\displaystyle\frac1{1-\frac1z}=\sum_{n=0}^\infty z^{-n}

so that by substitution, we can write

\displaystyle f(z) = 2 - \frac2z \sum_{n=0}^\infty (2z)^{-n} + \frac6z \sum_{n=0}^\infty z^{-n}

Now condense <em>f(z)</em> into one series:

\displaystyle f(z) = 2 - \sum_{n=0}^\infty 2^{-n+1} z^{-(n+1)} + 6 \sum_{n=0}^\infty z^{-n-1}

\displaystyle f(z) = 2 - \sum_{n=0}^\infty \left(6+2^{-n+1}\right) z^{-(n+1)}

\displaystyle f(z) = 2 - \sum_{n=1}^\infty \left(6+2^{-(n-1)+1}\right) z^{-n}

\displaystyle f(z) = 2 - \sum_{n=1}^\infty \left(6+2^{2-n}\right) z^{-n}

So, the inverse <em>Z</em> transform of <em>f(z)</em> is \boxed{6+2^{2-n}}.

4 0
3 years ago
What is the mechanical advantage of a pulley with 3 support ropes?
snow_tiger [21]

Answer:

The mechanical advantage is 3 to 1

Explanation:

A frictionless pulley with three support ropes carries equal tension on each of the ropes thus;

Tension in each pulley rope = T

Total tension in the 3 ropes = 3 × T = 3·T

Direction of the tension forces on each rope = Unidirectional

Total force provided by the 3 ropes = 3·T

Therefore, a force, T, applied at the end of the rope will result in a lifting force of 3·T

Hence, the mechanical advantage = 3·T to T which is presented as follows;

Mechanical \ advantage = \dfrac{3 \cdot T}{T}  = \dfrac{3}{1}

The mechanical advantage = 3 to 1.

5 0
4 years ago
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