All categories

2 years ago

Meaning of temporary stitches

Engineering

2 answers:

algol132 years ago

6 0

Answer:

They are use to hold garment or fabric pieces together before pernament stitches are made

9966 [12]2 years ago

5 0

Answer:

a temporary stitch is used for holding two or more layers of fabric together before a permanent stitch is made. Or if medical wise, not permanent.

Explanation:

You might be interested in

To become familiar with the general equations of plane strain used for determining in-plane principal strain, maximum in-plane s

lukranit [14]

Answer:

a) -1.46 x 10∧-5, 1.445x 10∧-4, -6.355 x 10∧-4

b) 3.926 x 10∧-4, -2.626 x 10∧-4

c) 6.552 x 10∧-4, 6.5 x 10∧-5

Explanation:

a) -1.46 x 10∧-5, 1.445x 10∧-4, -6.355 x 10∧-4

b) 3.926 x 10∧-4, -2.626 x 10∧-4

c) 6.552 x 10∧-4, 6.5 x 10∧-5

The explanation is shown in the attachment. I hope i have been able to help.

3 0

3 years ago

What is thermodynamics system? Briefly explain (i) control mass system (ii) control volume system. Comment briefly on control ma

olga2289 [7]

Explanation:

Thermodynamics system :

Thermodynamics system is a region or space in which study of matters can be done.The system is separated from surroundings by a boundary this boundary maybe flexible or fixed it depends on situations.The out side the system is called surroundings.

Generally thermodynamics systems are of three types

1.Closed system(control mass system)

Only energy transfer take place ,no mass transfer take place.

2.Open system(control volume system)

Both mass as well as energy transfer take place.

3.Isolated system

Neither mass or nor energy transfer take place.

At steady state ,property is did not changes with respect to time.

3 0

3 years ago

(a)Compute the electrical conductivity of a cylindrical silicon specimen 7.0 mm (0.28 in.) diameter and 57 mm (2.25 in.) in leng

igor_vitrenko [27]

Answer:

a) $\sigma = 12.2$ (Ω-m)^{-1}

b) Resistance = 121.4 Ω

Explanation:

given data:

diameter is 7.0 mm

length 57 mm

current I = 0.25 A

voltage v = 24 v

distance between the probes is 45 mm

electrical conductivity is given as

$\sigma = \frac{I l}{V \pi r^2}$

$\sigma = \frac{0.25 \times 45\times 10^{-3}}{24 \pi [\frac{7 \times 10^{-3}}{2}]^2}$

$\sigma = 12.2$ (Ω-m)^{-1}[/tex]

$Resistance = \frac{l}{\sigma A}$

$= \frac{l}{ \sigma \pi r^2}$

$= \frac{57 \times 10^{-3}}{12.2 \times \pi [\frac{7 \times 10^{-3}}{2}]^2}$

Resistance = 121.4 Ω

8 0

3 years ago

Determine the static pressure to stagnation pressure ratio associated with the following motion in standard air: (a) a runner mo

vredina [299]

Answer: a) 0.00017

b) 0.0013

c) 0.0022

d) 0.017

Explanation:

3 0

3 years ago

Air enters a 28-cm diameter pipe steadily at 200 kPaand 208C with a velocity of 5 m/s. Air is heated as it flows, and leaves the

Alina [70]

Answer:

(a) $\dot V_1$ = 0.308 m³/s

(b) $\dot m$ = 0.732 kg/m³

Explanation:

(a) The volume flow rate is given by the cross sectional area of the pipe × Velocity of flow of air

Diameter of pipe = 28 cm = 0.28 m

The cross sectional area, A, of the pipe = 0.28²/4×π = 0.0616 m²

Volume flow rate = 5 × 0.0616 = 0.308 m³/s

$\dot V_1$ = 0.308 m³/s

(b) From the general gas equation, we have;

p₁v₁ = RT₁ which gives;

p₁/ρ₁ = RT₁

ρ₁ = p₁/(RT₁)

Where:

ρ₁ = Density of the air

p₁ = 200 kPa

T₁ = 20 C =

R = 0.287 kPa·m³/(kg·K)

ρ₁ = 200/(0.287 ×293.15) = 2.377 kg/m³

The mass flow rate = Volume flow rate × Density

The mass flow rate, $\dot m$ = 2.377×0.308 = 0.732 kg/m³

$\dot m$ = 0.732 kg/m³

ρ₂ = p₂/(RT₂)

Where:

p₂ = Pressure at exit = 180 kPa

T₂ = Exit temperature = 40°C = 273.15 + 40 = 313.15 K

∴ ρ₂ = 180/(0.287×313.15) = 2.003 kg/m³

$\dot m$ = ρ₂× $\dot V_2$

$\dot V_2$ = $\dot m$ /ρ₂ = 0.732/2.003 = 0.366 m³/s

$\dot V_2$ = v₂ × A

v₂ = $\dot V_2$ /A = 0.366/0.0616 = 5.94 m/s.

v₂ = 5.94 m/s.

5 0

3 years ago

Meaning of temporary stitches​

Meaning of temporary stitches