Answer:
A. National Highway Safety Act
Explanation:
The National Highway Safety Act establishes general guidelines concerning licensing, vehicle registration and inspection, and traffic laws for state regulations. The act was made in 1966 to reduce the amount of death on the highway as a result of increase in deaths by 30% between 1960 and 1965
National Traffic and Motor Vehicle Safety Act regulates vehicle manufacturers by ensuring national safety standards and issuance recalls for defective vehicles
Uniform Traffic Control Devices Act defines shapes, colors and locations for road signs, traffic signals, and road markings
Answer:
please give brainliest my brother just got the corona virus
Explanation:
this is my brothers account he wants to get 5 brainliest
Answer:
576.21kJ
Explanation:
#We know that:
The balance mass ![m_{in}+m_{out}=\bigtriangleup m_{system}](https://tex.z-dn.net/?f=m_%7Bin%7D%2Bm_%7Bout%7D%3D%5Cbigtriangleup%20m_%7Bsystem%7D)
so, ![m_e=m_1-m_2](https://tex.z-dn.net/?f=m_e%3Dm_1-m_2)
![Energy \ Balance\\E_{in}-E_{out}=\bigtriangleup E_{system}\\\\\therefore Q_i_n+m_eh_e=m_2u_2-m_1u_1](https://tex.z-dn.net/?f=Energy%20%5C%20Balance%5C%5CE_%7Bin%7D-E_%7Bout%7D%3D%5Cbigtriangleup%20E_%7Bsystem%7D%5C%5C%5C%5C%5Ctherefore%20Q_i_n%2Bm_eh_e%3Dm_2u_2-m_1u_1)
#Also, given the properties of water as;
![(P_1=2Mpa,T_1=300\textdegree C)->v_1=0.12551m^3/kg,u_1=2773.2kJ/kg->h_1=3024.2kJ/kg\\\\(P_2=2Mpa,T_1=500\textdegree C)->v_2=0.17568m^3/kg,u_1=3116.9kJ/kg->h_1=3468.3kJ/kg](https://tex.z-dn.net/?f=%28P_1%3D2Mpa%2CT_1%3D300%5Ctextdegree%20C%29-%3Ev_1%3D0.12551m%5E3%2Fkg%2Cu_1%3D2773.2kJ%2Fkg-%3Eh_1%3D3024.2kJ%2Fkg%5C%5C%5C%5C%28P_2%3D2Mpa%2CT_1%3D500%5Ctextdegree%20C%29-%3Ev_2%3D0.17568m%5E3%2Fkg%2Cu_1%3D3116.9kJ%2Fkg-%3Eh_1%3D3468.3kJ%2Fkg)
#We assume constant properties for the steam at average temperatures:![h_e=\approx(h_1+h_2)/2](https://tex.z-dn.net/?f=h_e%3D%5Capprox%28h_1%2Bh_2%29%2F2)
#Replace known values in the equation above;![h_e=(3024.2+3468.3)/2=3246.25kJ/kg\\\\m_1=V_1/v_1=0.19m^3/(0.12551m^3/kg)=1.5138kg\\\\m_2=V_2/v_2=0.19m^3/(0.17568m^3/kg)=1.0815kg](https://tex.z-dn.net/?f=h_e%3D%283024.2%2B3468.3%29%2F2%3D3246.25kJ%2Fkg%5C%5C%5C%5Cm_1%3DV_1%2Fv_1%3D0.19m%5E3%2F%280.12551m%5E3%2Fkg%29%3D1.5138kg%5C%5C%5C%5Cm_2%3DV_2%2Fv_2%3D0.19m%5E3%2F%280.17568m%5E3%2Fkg%29%3D1.0815kg)
#Using the mass and energy balance relations;
![m_e=m_1-m_2\\\\m_e=1.5138-1.0815\\\\m_e=0.4323kg](https://tex.z-dn.net/?f=m_e%3Dm_1-m_2%5C%5C%5C%5Cm_e%3D1.5138-1.0815%5C%5C%5C%5Cm_e%3D0.4323kg)
#We have
: we replace the known values in the equation as;
![Q_i_n+m_eh_e=m_2u_2-m_1u_1\\\\Q_i_n=0.4323kg\times3246.2kJ/kg+1.0815kg\times3116.9-1.5138kg\times2773.2kJ/kg\\\\Q_i_n=573.21kJ](https://tex.z-dn.net/?f=Q_i_n%2Bm_eh_e%3Dm_2u_2-m_1u_1%5C%5C%5C%5CQ_i_n%3D0.4323kg%5Ctimes3246.2kJ%2Fkg%2B1.0815kg%5Ctimes3116.9-1.5138kg%5Ctimes2773.2kJ%2Fkg%5C%5C%5C%5CQ_i_n%3D573.21kJ)
#Hence,the amount of heat transferred when the steam temperature reaches 500°C is 576.21kJ
Answer:
There are 6 types of pressure control valves and their function is to regulate the pressure below a threshold level within safe limits and to maintain and control pressure of a particular circuit.
Explanation:
The six type of Pressure valve with their functions are given below:
a. Unloading Valve:
These type of pressure valve are used to pour fluid into the container at very low or no pressure.
b. Safety valve:
These are used when the pressure within the vessel is in excess as inside temperature is near about preset [point point then these valves are open to release the extra pressure and are closed once normal conditions are regained.
c. Pressure Reducing Valve:
These are basically used for the control of the pressure in downstream not exceeding the design limits.
d. Pressure Relief Valves:
These are basically used to limit and regulate the pressure of any system.
e. Counter Balance Valve:
These are used to develop pressure in the reverse direction at the actuator's return line in order to keep the load under control.
f. Sequence Valve:
These are used to maintain sequence or order in the operations of two parts or branches.
Answer:
a) 42.08 ft/sec
b) 3366.33 ft³/sec
c) 0.235
d) 18.225 ft
e) 3.80 ft
Explanation:
Given:
b = 80ft
y1 = 1 ft
y2 = 10ft
a) Let's take the formula:
![10*2 = \sqrt{1 + 8f^2 - 1](https://tex.z-dn.net/?f=%2010%2A2%20%3D%20%5Csqrt%7B1%20%2B%208f%5E2%20-%201)
1 + 8f² = (20+1)²
= 8f² = 440
f² = 55
f = 7.416
For velocity of the faster moving flow, we have :
V1 = 42.08 ft/sec
b) the flow rate will be calculated as
Q = VA
VA = V1 * b *y1
= 42.08 * 80 * 1
= 3366.66 ft³/sec
c) The Froude number of the sub-critical flow.
V2.A2 = 3366.66
Where A2 = 80ft * 10ft
Solving for V2, we have:
= 4.208 ft/sec
Froude number, F2 =
F2 = 0.235
d)
= 18.225ft
e) for critical depth, we use :
= 3.80 ft