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katrin [286]
3 years ago
10

DE QUE MANERA LA ALEGRIA NOS AYUDA A CONSEGIR AMIGOS ≤→ω←≥

Engineering
1 answer:
madreJ [45]3 years ago
6 0

Answer: Nos hace más valientes y nos empuja a hacerlo. >_<

Explanation:

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Gold and silver rings can receive an arc and turn molten. True or False
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Read 2 more answers
Write multiple if statements: If carYear is before 1967, print "Probably has few safety features." (without quotes). If after 19
Free_Kalibri [48]

Answer:

The solution code is written in Python 3.

  1. carYear = 1995
  2. if(carYear < 1967):
  3.    print("Probably has few safety features.\n")
  4. if(carYear > 1970):
  5.    print("Probably has head rests. \n")
  6. if(carYear > 1991):
  7.    print("Probably has electronic stability control.\n")
  8. if(carYear > 2002):
  9.    print("Probably has airbags. \n")

Explanation:

Firstly, create a variable, <em>carYear</em> to hold the value of year of the car make. (Line 1)

Next, create multiple if statements as required by the question (Line 3-13). The operator "<" denotes "smaller" and therefore <em>carYear < 1967</em> means any year before 1967. On another hand, the operator ">" denotes "bigger" and therefore <em>carYear > 1970 </em>means any year after 1970.

The print statement in each of the if statements is done using the Python built-in function <em>print()</em>. The "\n" is an escape sequence that create a new line at the end of each printed phrase.

5 0
3 years ago
If an airplane travels at a speed of 1120 km/hr at an altitude of 15 km, what is the required speed at an altitude of 8 km to sa
jek_recluse [69]

Answer:

1170 km/hr

Explanation:

Let's first state the formula to be used

c = √(KRT)

The temperature at an altitude of 15km is -56.5° C

Let's not convert this to °K, we have

-56.5° + 273.15 = 216.65° K

Also, the temperature at 8km is -36.9° C, on converting to °K we have

-36.9° + 273.15 = 236.25° K

Then again, we look for the speed at both 15 km and 8 km both of which are 295 m/s and 308 km

Finally, we use the mach similarity formula

(V/c) of 15km = (V/c) of 8km

V of 8km = c of 8km * (V/c) of 15km

V of 8km = 1170 km/hr

6 0
2 years ago
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