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AlekseyPX
2 years ago
8

I am very confused with this help and I don’t even have a example

Mathematics
2 answers:
klio [65]2 years ago
6 0
Your teacher crazy what even is this
Nikolay [14]2 years ago
3 0

Answer:

5x+4=? this is what i got

Step-by-step explanation:

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Solve the inequality<br> -1/3h ≥ 7<br> A. h ≥ –21<br> B. h ≤ 7 1/3<br> C. h ≤ –21<br> D. h ≥ -2 1/3
JulsSmile [24]
The Answer Is C Fam...................
8 0
3 years ago
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If the tangent line to y = f(x) at (7, 4) passes through the point (0, 3), find f(7) and f '(7).
jarptica [38.1K]
Hello : 
f'(7) = the slope of the tangent line : let  A(7,4)    B(0,3)<span>
<span>the slope is :   (YB - YA)/(XB -XA)= (3-4)/(0-7) = -1/-7 = 1/7=f'(7)
the equation of the tangent line is :
y-3 = 1/7 (x-0)
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the line tangent and the graph of : f </span></span><span>passes through the point A(7, 4)
x= 7 y=4 so : f(7) =4</span>
4 0
2 years ago
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
2 years ago
Huh?! Its me DaBaby less gooo i need your help with this question. Yeah Yeah!
Misha Larkins [42]

Answer:

Imaoo

Step-by-step explanation:

answer: C

4 0
2 years ago
Read 2 more answers
Which number is closest to √18
Mars2501 [29]

Answer:

4.2 or 4

Step-by-step explanation:

√18 = 4.24264068712

or 4.2

or 4

8 0
3 years ago
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