Answer: option D. 4.5 seconds.
Explanation:
The equilibrium reaction is H₂O ⇄ H₂ + O₂
The chemical equilibrium is a dynamic one. Two reactions are happening symultaneously: the forward reaction (H₂O → H₂ + O₂) ,to the right, and the reverse reaction (H₂O ← H₂ + O₂), to the left. At equilibrium both reactions have the same rate, which makes that the total, measurable quantity of reactants and products remain constant.
In the figure you see:
- The vertical axis measures concentration.
- The horizontal axis measures time (seconds).
- The two blue lines, the concentrations of H₂ and O₂, become flat (reach a zero slope) between 4 and 5 seconds.
- The red line, the concentration of H₂O, becomes flat, also, between 4 and 5 seconds.
- Hence, the concentrations of the reactant and the products do not change after that time meaning that the reaction has reached the equilibrium at about 4.5 seconds.
Answer:
See Explanation
Explanation:
Elements in group fourteen are mostly known to form compounds in which there are four electron domains leading to a tetrahedral electron domain geometry.
However, the presence of lone pairs affects the shape of the molecule. SnCl3− has four electron domains, three of them are bond pairs while one is a lone pair. The shape of the molecule is based on a tetrahedron, however the observed geometry is trigonal pyramidal due to the presence of the lone pair. Its bond angle is now less than the predicted 109 degrees.
Answer:
[HI] = 0.264M
Explanation:
Based on the equilibrium:
2HI(g) ⇄ H₂(g) + I₂(g)
It is possible to define Kc of the reaction as the ratio between concentration of products and reactants using coefficients of each compound, thus:
<em>Kc = 0.0156 = [H₂] [I₂] / [HI]²</em>
<em />
As initial concentration of HI is 0.660mol / 2.00L = <em>0.330M, </em>the equlibrium concentrations will be:
[HI] = 0.330M - 2X
[H₂] = X
[I₂] = X
<em>Where X is reaction coefficient.</em>
<em />
Replacing in Kc:
0.0156 = [X] [X] / [0.330M - 2X]²
0.0156 = X² / [0.1089 - 1.32X + 4X²
]
0.00169884 - 0.020592 X + 0.0624 X² = X²
0.00169884 - 0.020592 X - 0.9376 X² = 0
Solving for X:
X = - 0.055 → False solution, there is no negative concentrations
X = 0.0330 → Right solution.
Replacing in HI formula:
[HI] = 0.330M - 2×0.033M
<h3>[HI] = 0.264M</h3>
The lower you go, the more acidic. The higher you go, the more alkaline. Your answer would most likely be 6.
Answer:
See attached picture.
Explanation:
Hello,
In this case, for the given name, you can verify the structure on the attached picture, wherein you can see verify the presence of both the ethyl and methyl radicals at the third carbon as well as the triple bond at the first carbon.
Best regards.
