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Ksenya-84 [330]
3 years ago
11

The reduction potential (E0′) of a substance reflects its tendency to donate or accept electrons. The larger the difference (ΔE0

′) between the reduction potentials of the electron donor and the electron acceptor, __________.A) the greater the change in free energy (ΔG0′), and the less energy is releasedB) the closer the substances are on the electron towerC) the more enzymes will be required to catalyze the reaction(s)D) the greater the change in free energy (ΔG0′), and the greater the energy released
Chemistry
1 answer:
mote1985 [20]3 years ago
8 0

Answer:

The greater the change in free energy (ΔG0′), and the greater the energy released

Explanation:

Recall that the change in free energy is given by:

∆G°'= nFE°'

But E° is given by E°acceptor - E°donor

Hence the greater the difference between E°acceptor and E°donor, the greater the value of E° and consequently the greater the value of ∆G° and the energy released.

Note: E°acceptor and E°donor refer to reduction potentials of donor and acceptor

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Many computer chips are manufactured from silicon, which occurs in nature as SiO2. When SiO2 is heated to melting, it reacts wit
riadik2000 [5.3K]

Answer:

A) SiO2 is the limiting reactant

B) Theoretical yield= 72333.3g

C) % yield =91.5%

Explanation:

SiO2(s) + 2C(s) --------------> Si(s) + 2CO(g)

n(SiO2)= 155000/60 = 2583.33 mols

n(C)= 79000/12= 3291.66 mols

a)SiO2 is the limiting reactant

According to the balanced reaction equation,

60g of SiO2 produced 28g of SiO2

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Therefore theoretical yield of Si= 72333.3g

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5 0
3 years ago
In Rutherford's Gold foil experiment, were the alpha particles directed to different areas of the gold foil or only the same spo
MrRissso [65]

Answer:

See explanation

Explanation:

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However, some of the alpha particles were deflected through large angles, in Rutherford's interpretation, the deflected alpha particles had hit the dense positive core of the atom which he called the nucleus.

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8 0
3 years ago
For the hypothetical reaction: A + B ---> 2C, write an expression that relates the disappearance of A and B to the appearance
forsale [732]

Answer:

Rate expression has been given below

Explanation:

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So, rate of disappearance of both A and B are one half of rate of appearance of B

Hence rate expression can be represented as:

Rate=\frac{-\Delta [A]}{\Delta t}=\frac{-\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}

where \frac{-\Delta [A]}{\Delta t} is rate of disappearance of A, \frac{-\Delta [B]}{\Delta t} is rate of disappearance of B and \frac{\Delta [C]}{\Delta t} rate of appearance of C

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The empirical formula of the sugar glucose is ch2o. if the relative molecular mass of glucose is measured to be 180.16 g/mol the
ZanzabumX [31]

Answer:

18016

Explanation:

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7 0
1 year ago
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