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vovikov84 [41]
3 years ago
14

What are the units for the measurements of radioactive element activity?

Chemistry
1 answer:
torisob [31]3 years ago
7 0

Answer:

Bq

Explanation:

The number of decays per second, or activity, from a sample of radioactive nuclei is measured in becquerel (Bq), after Henri Becquerel. One decay per second equals one becquerel.

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HELP ME PLEASE !!!!!!!!!!!
xenn [34]

Answer:

1231

Explanation:

nnfjjkdnsggjnSVDDK and that how u get the answer i a grammer

6 0
3 years ago
What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?
lawyer [7]
  • Density=2.35g/mL
  • Mass=33.67g

\\ \star\sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \star\sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \star\sf\longmapsto Volume=\dfrac{33.67}{2.35}

\\ \star\sf\longmapsto Volume=14.32mL

6 0
2 years ago
Write einstein's equation that explains the energy from nuclear reactions. _________ use the caret symbol (^) to show an exponen
Katen [24]
I would say it should be Einstein's famous equation of e=mc^2 which means energy =mass x the speed of light squared. With this equation Einstein showed that energy comes from a mass travelling at the speed of light squared which is a fundamental equation to explain physical phenomena.
4 0
3 years ago
Read 2 more answers
Water vapor changing to liquid water
kiruha [24]

Explanation:

When water vapour changes to liquid water then this process is known as condensation.

For example, when lid is placed in a hot water filled pan then after sometime vapours appear on the surface of lid. When temperature of water decreases then water vapours convert into liquid form.

Thus, we can conclude that in condensation water vapor changes to liquid water.

4 0
3 years ago
Read 2 more answers
Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
Helen [10]

Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

Molarity of HCl solution = 4.25 M

Mass of CaCO₃ = 8.75 g

Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

Volume of HCl:

Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

41 mL

8 0
2 years ago
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