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3 years ago

A number written in just numbers is in:

Mathematics

1 answer:

Elena-2011 [213]3 years ago

7 0

Answer:

Standard form

Step-by-step explanation:

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Which measurement is not equal to 3 m 30 dm or 300 cm or 3000 mm or 3000 cm

Ainat [17]

3000cm because if you look at the variables there is no more letter m's than anything so if you cancel out and see what is equal to 30 then you get 3000cm!!!!!

4 0

3 years ago

Read 2 more answers

I'm almost done with schooling any help?

melisa1 [442]

Answer:

The ordered pair that corresponds to point P is: (4, 2)

Step-by-step explanation:

It is clear from the graph that the point P is located at the location (4, 2).

In other words,

at x = 4, y = 2

It means:

The x-coordinate of the point P is: x = 4

The y-coordinate of the point P is: y = 2

Thus, the location of the point P → P(x, y) = P(4, 2)

Please check the attached graph.

Therefore, we conclude that:

The ordered pair that corresponds to point P is: (4, 2)

6 0

3 years ago

Given: F(x) = 5x - 6 and G(x) = x - 4

fomenos

Answer:

Correct choice is $\dfrac{x+26}{5}$

Step-by-step explanation:

1. If $F(x)=5x-6,$ then you can find the inverse $F^{-1}(x):$

$y=5x-6,\\ \\5x=y+6,\\ \\x=\dfrac{y+6}{5},\\ \\F^{-1}(x)=\dfrac{x+6}{5}.$

2. If $G(x)=x-4,$ then

$y=x-4,\\ \\x=y+4,\\ \\G^{-1}(x)=x+4.$

3. Hence,

$G^{-1}(F^{-1}(x))=G^{-1}\left(\dfrac{x+6}{5}\right)=\dfrac{x+6}{5}+4=\dfrac{x+26}{5}.$

7 0

4 years ago

(05.07 MC)

sp2606 [1]

Given that the net of the square pyramid is as shown above, the surface are of the pyramid will be given by:
SA=(number of triangles)*(area of triangle)*(area of square base)
area of one triangle will be:
A=1/2*base*height
A=1/2*0.8*0.75
A=0.3 sq. inches

area of the square base will be:
A=0.75*0.75
A=0.5625
Therefore the surface area will be:
SA=4*0.3*0.5625
SA=0.675 sq. inches

5 0

3 years ago

If alpha beta are the roots of the equation

Vikki [24]

Answer:

Step-by-step explanation:

Hello, I believe that we can consider a different from 0.

By definition of the roots we can write.

$ax^2+bx+c=a(x-\alpha)(x-\beta)=a(x^2-(\alpha + \beta)x+\alpha \cdot \beta)\\\\\text{So we can say that:}\\\\\alpha + \beta = \dfrac{-b}{a}\\\\\alpha \cdot \beta=\dfrac{c}{a}\\\\\text{So the expected quadratic equation is}\\\\(x+\dfrac{b}{a})(x-\dfrac{c}{a})=0\\\\ \Large \boxed{\sf \bf \ (ax+b)(ax-c)=0 \ }$

Thank you

8 0

3 years ago