The Area of the square is (side)^2
side is given to be 2^(4/9)
SO,
side^2 = [2^(4/9)]^2 = 2^(4/9 * 2) = 2^(8/9)
so the area of square is 2^(8/9) sq. inches.
Answer:
3.04m
Step-by-step explanation:
Time taken to swing the rope = 3.5s
Length of the rope = L
T = 2π√(L / 9.8)
3.5 = 2π√(L / 9.8)
take the square of both sides
(3.5)² =[2π√(L/9.8)]²
12.25 = 39.48 × (L / 9.8)
12.25 = 39.48L / 9.8
39.48L = 12.25 × 9.8
39.48L = 120.05
L = 120.05 / 39.48
L = 3.04m
The length of the rope is 3.04m
Answer:

Step-by-step explanation:
Objective: Use the rules of Algebra to isolate y.




Answer:
D. 2019
Step-by-step explanation:
So I started by rewriting the function f(x)
1000 = 10^3 so
f(x)=10^3 times 1.03^x
1.03 = 103/100 so
f(x)= 10^3 times (103/100)^x
to raise a fraction to a power you just raise the numerator and denominator to that power so
f(x)= 10^3 times 103^x/100^x
change it to exponential form with a base of 10
f(x)=10^3 times 103^x/10^2x
then you can reduce it with the 10^3
f(x)=103^x/10^2x-3
so now that thats in more of a standard form you can find the intersection of the two functions
which is at (9.012,1305.244)
x is the number of years after 2010, so they will be equal ~9 years after 2010, which is 2019.
<span>All you have to do is learn Chebyshev's theorem in terms of k, then
substitute 2 for k.
Here is Chebyshev's theorem in terms of k:
According to Chebyshev's theorem, the proportion of values
from a data set that is further than standard deviations
from the mean is at most .
Then when you plug in 2 for k, you get:
According to Chebyshev's theorem, the proportion of values
from a data set that is further than standard deviations
from the mean is at most .
or writing for ,
According to Chebyshev's theorem, the proportion of values
from a data set that is further than standard deviations
from the mean is at most .
Or if you prefer a decimal answer:
According to Chebyshev's theorem, the proportion of values
from a data set that is further than standard deviations
from the mean is at most .
Or if you prefer a percent answer:
According to Chebyshev's theorem, the proportion of values
from a data set that is further than standard deviations
from the mean is at most %.
</span>