Create a hypothesis, design an experiment the list varies really
Answer: Li is the reducing agentg and O is the oxidizing agent.
Explanation:
1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.
2) The given reaction is:
4Li(s) + O₂ (g) → 2 Li₂O(s)
3) Determine the oxidation states of each atom:
Li(s): oxidation state = 0 (since it is alone)
O₂ (g): oxidation state = 0 (since it is alone)
Li in Li₂O (s) +1
O in Li₂O -2
That because 2× (+1) - 2 = 0.
4) Determine the changes:
Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.
O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.
Answer:
The total pressure is 0,804 atm
Explanation:
We use Dalton's law according to which the sum of the partial pressures is equal to the total pressure of a gas mixture. We convert the pressure in Pascals to atmosphere (it can also be done in reverse):
101300Pa ----1 atm
4500Pa----x= (4500Pa x 1atm)/101300Pa= 0,044 atm
P total= p1 + p2= 0,76 atm + 0,044 atm=0,804 atm
HCl + NaOH ---> NaCl + H20
If you follow guidance from other questions I have already answered for you, you will see that the above equation is balanced as it is.
Answer:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
Explanation:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
H+
O2-
OH-
Ba2+
Ca2+
NO3-
P 5+, 3+, 3-
H2O
