What is the concentration in mass percent of a solution prepared from 50.0g nacl and 150.0g of water?
1 answer:
M(NaCl)=50.0 g
m(H₂O)=150.0 g
m(solution)=m(NaCl)+m(H₂O)
w(NaCl)=100m(NaCl)/m(solution)=100m(NaCl)/{m(NaCl)+m(H₂O)}
w(NaCl)=100*50.0/(50.0+150.0)=25%
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