Answer:
The pH of the buffer is 4.77
Explanation:
Using Henderson-Hasselbalch equation we can solve the pH of the buffer:
pH = pKa + log [A⁻] / [HA]
<em>Where pH is the pH of the buffer</em>
<em>pKa is -log Ka = 5.056</em>
<em>[A⁻] = [NaA] = 0.2M</em>
<em>[HA] = 0.39M</em>
<em />
Replacing:
pH = 5.056+ log [0.2] / [0.39]
pH = 4.77
<h3>The pH of the buffer is 4.77</h3>
<em />
When m for water is only 5 % so, m for the acid is (m%) = 95%
and D = 1.84 g/ml, assume 1 L of solution therefore,
1- D= m / v
m = D x v = 1.84 g/ml x 1 L x 10^3 ml /L
= 1840 g solution
2- m% = m acid / m sol x 100 %
m acid = 1840 g H2So4 x 0.95
= 1750 g H2So4
3- n = 1750 g H2So4 x 1 mol H2So4 x 98.09 H2So4
= 17.8 mol H2So4
4- So the molarity of { H2So4} = n / v = 17.8 mol H2So4 / 1 L
= 17.8 M
Explanation:
Hello, there are alot method to separate the impurities from water. One of those & best method for purification of water is Distillation.
During distillation the given apparatus are set as shown in figure. After arrangement we put the impure water in distillation flask & there are two mouth of flask one is attached to condenser & other is covered. There are two tubes in the middle of the condenser in which water comes in from one and water goes out from the other and this happens continuously. The condenser is used to convert the collected water vapours into liquid water so that it can be collected easily in recieving flask.
Answer:
Nuclear fusion is a kind of nuclear reaction in which two lighter nuclei combine under suitable conditions to form heavier nuclei under suitable conditions
Explanation:
C = Q / M * ΔT
Δf - Δi = 42.0ºC - 12.0ºC = 30.0ºC
C = 226 J / 58.3 * 30.0
C = 226 / 1749
C = 0.129 J/gºC
hope this helps!
