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3 years ago

How would you write 16,340 in scientific notation with 2 significant figures

Chemistry

1 answer:

Murrr4er [49]3 years ago

5 0

Answer:

D) 1.6 x 10^4

Explanation:

I just took the took

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Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r

denis23 [38]

Answer :

(1) The frequency of photon is, $3\times 10^{10}Hz$

(2) The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = $1.0cm=0.01m$ (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of photon

$\lambda$ = wavelength of photon

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$\nu=\frac{3\times 10^8m/s}{0.01m}$

$\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz$ $(1Hz=1s^{-1})$

The frequency of photon is, $3\times 10^{10}Hz$

(2) Now we have to calculate the energy of photon.

Formula used :

$E=h\times \nu$

where,

$\nu$ = frequency of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})$

$E=1.988\times 10^{-23}J/photon$

The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) Now we have to calculate the energy in J/mol.

$E=1.988\times 10^{-23}J/photon$

$E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)$

$E=11.97J/mol$

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0

3 years ago

Read 2 more answers

The kinetic energy within molecules of an object _ when heat is added? Increases decreases or remains the same

kotegsom [21]

The kinetic energy of an object increases when heat is added.

6 0

3 years ago

What is the independent variable?

olganol [36]

X is always the independent variable

6 0

4 years ago

7. A human's appendix, wisdom teeth, and a dew claw are

Ugo [173]

Answer:

Vestigial Structures

Explanation:

Structures that were needed for an organism's ancestor, but no longer required for survival for the current organism. We needed our wisdom teeth and appendix in order to eat tougher foods, but now we do not need those to survive. But, we still have them.

8 0

3 years ago

You measure the emission spectrum of an atom that you suspect to be hydrogen. You have no absolute calibration of the wavelength

trapecia [35]

Answer:

Explanation:

What we need to do here is to determine the ratios by using the Rydberg equation starting with the transition to n1 = 1, 2,3, etc and see which one fits the data. Remember the question states that they are series and the wavelengths will be for increasing energy levels.

1/λ = Rh x ( 1/n₁² - 1/n₂²)

Lyman series ( n₁=1 and n₂= 2,3 etc) for the first two lines, the ratios will be:

1/λ₁ /1/λ₂ =(1/1 -1/ 2²) / (1/1 -1/ 3²) ⇒ 0.84 ≠ 0.74 (the first ratio)

For Balmer series n₁ = 2 and n₂ = 3,4,5, etc

1/λ₁ /1/λ₂ =(1/4 -1/3²) / (1/4 -1/4²) ⇒ 0.741 = 0.741 (match!)

Lets use the third line to check our answer:

1/λ₁ /1/λ₂ =(1/4 -1/3²) / (1/4 -1/5²) = 0.66

5 0

3 years ago