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3 years ago

there are 45 questions on your math exam.you answered 8/10 of them correctly.how many questions did you answer correctly?

Mathematics

1 answer:

Nonamiya [84]3 years ago

6 0

Answer:

you would have gotten 36 questions correct :)

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JulijaS [17]

Answer:

The shark is furthest from sea level (18 feet below sea level)

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3 years ago

Find the length of the hypotenuse. Round your answer to the nearest hundredth

laiz [17]

Answer:

c^2=a^2+b^2

=7^2+3^2

=49+9

=58

c^2=58

$\sqrt{58 = 7.6}$

the answer is C=7.62..

8 0

3 years ago

Read 2 more answers

The 8th-grade class is fundraising for their spring trip. They need to raise a minimum of $2,000. The class is selling mugs at $

serg [7]

Answer:

If you multiply the 7 by 15 using the AZB formula you will get the asnwer^5 to divide the answer by .05

Step-by-step explanation:

4 0

3 years ago

In how many ways can 15 people be divided into two groups, one group with 10 and the other with 5 people?

viktelen [127]

Answer:

Step-by-step explanation:

Given that there are 15 people and they should be divided into two groups one with 10 and the other with 5 people.

First group 10 persons can be selected from 15 in 15C10 ways.

Remaining 5 would automatically be put in group 2.

Hence no of ways $= 15C5 =\frac{15!}[10!5!} \\=3003$

5 0

3 years ago

Please help!! 10 points

hichkok12 [17]

Answer:

We conclude that:

$\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}$

Hence, option B is correct.

Step-by-step explanation:

Given the expression

$\sqrt[3]{200k^{15}}$

Apply radical rule:

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

so the expression becomes

$\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}$

first solving

$\sqrt[3]{k^{15}}$

Apply radical rule: $\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\sqrt[3]{k^{15}}=k^{\frac{15}{3}}=k^5$

then solving

$\sqrt[3]{200}$

prime factorization: 200: 2³ · 5²

$=\sqrt[3]{2^3\cdot \:5^2}$

Apply radical rule:

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt[3]{2^3}\sqrt[3]{5^2}$

Apply radical rule:

$\sqrt[n]{a^n}=a,\:\quad \:a\ge 0$

$=2\sqrt[3]{5^2}$

Thus, the main expression becomes

$\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}$

$=2k^5\sqrt[3]{25}$

Therefore, we conclude that:

$\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}$

Hence, option B is correct.

3 0

3 years ago