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2 years ago

6. 200 pages to 600 pagespercentage of change

Mathematics

1 answer:

adell [148]2 years ago

7 0

Answer:

What

Step-by-step explanation:

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Can you have an 'All Real Numbers' solution for inequalities? If so, give an example.

irga5000 [103]

Answer:

yes

Step-by-step explanation:

x+7>x+3

7 0

3 years ago

Solve this proportion: 8/x = 2/5. x =

Taya2010 [7]

8/x= 2/5

8•5= 2•x

40=2x

40/2= x

20= x

3 0

2 years ago

What percent of 146 is 9 ?

sukhopar [10]

We need to cross multiply to find this one.

9/146 = x/100
X100 X100
9 /146 = x
x = 6.164383562

5 0

3 years ago

Read 2 more answers

Simplify.<br> -2(x+3)+6x

brilliants [131]

−2(x+3)+6x

Distribute:

=(−2)(x)+(−2)(3)+6x

=−2x+−6+6x

Combine Like Terms:

=−2x+−6+6x

=(−2x+6x)+(−6)

=4x+−6

4 0

2 years ago

Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

6 0

2 years ago

6. 200 pages to 600 pagespercentage of change​

6. 200 pages to 600 pagespercentage of change