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2 years ago

PLEEEEAAASESE HELP AGAIN! ID REALLY APPRECIATE IT

Mathematics

2 answers:

Lyrx [107]2 years ago

5 0

The slope is -5/4 :)

anastassius [24]2 years ago

4 0

$\huge\fbox\orange{A} \huge\fbox\red{N}\huge\fbox\blue{S}\huge\fbox\green{W}\huge\fbox\gray{E}\huge\fbox\purple{R}$

$- \frac{5}{4}$

$\huge\mathsf\colorbox{white}{See also, Attachment}$

Reduced: -1.25

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Identify the vertex and the y-intercept of the graph of each function. Show your work

olga2289 [7]

vertex
y = 3(x - 2)² - 4
y = 3((x - 2)(x - 2)) - 4
y = 3(x² - 2x - 2x + 4) - 4
y = 3(x² - 4x + 4) - 4
y = 3(x²) - 3(4x) + 3(4) - 4
y = 3x² - 12x + 12 - 4
y = 3x² - 12x + 8
3x² - 12x + 8 = 0
x = -(-12) +/- √((-12)² - 4(3)(8))
 2(3)
x = 12 +/- √(144 - 96)
 6
x = 12 +/- √(48)
 6
x = 12 +/- 6.93
 6
x = 2 +/- 1.155
x = 2 + 1.155 x = 2 - 1.155
x = 3.155 x = 0.845
y = 3x² - 12x + 8
y = 3(3.155)² - 12(3.155) + 8
y = 3(1.334025) - 3.786 + 8
y = 4.002075 - 3.786 + 8
y = 0.216075 + 8
y = 8.216075
(x, y) = (3.155, 8.216075)
or
y = 3x² - 12x + 8
y = 3(0.845)² - 12(0.845) + 8
y = 3(0.714025) - 10.14 + 8
y = 2.142075 - 10.14 + 8
y = -7.857925 + 8
y = 0.142675
(x, y) = (0.845, 0.142675)
y-intercept
y = 3x² - 12x + 8
y = 3(0)² - 12(0) + 8
y = 3(0) - 0 + 8
y = 0 - 0 + 8
y = 0 + 8
0 = -y + 8
y = 8
(x, y) = (0, 8)
-------------------------------------------------------------------------------------------
vertex
y = 4(x - 5)² = 1
y = 4(x - 5)² - 1
y = 4((x - 5)(x - 5)) - 1
y = 4(x² - 5x - 5x + 25) - 1
y = 4(x² - 10x + 25) - 1
y = 4(x²) - 4(10x) + 4(25) - 1
y = 4x² - 40x + 100 - 1
y = 4x² - 40x + 99
4x² - 40x + 99 = 0
x = -(-40) +/- √((-40)² - 4(4)(99))
 2(4)
x = 40 +/- √(1600 - 1584)
 8
x = 40 +/- √(16)
 8
x = 40 +/- 4
 8
x = 5 +/- 1/2
x = 5 + 1/2 x = 5 - 1/2
x = 5 1/2 x = 4 1/2
y = 4x² - 40x + 99
y = 4(5 1/2)² - 40(5 1/2) + 99
y = 4(30 1/4) - 220 + 99
y = 121 - 220 + 99
y = -99 + 99
y = 0
(x, y) = (5 1/2, 0)
or
y = 4x² - 40x + 99
y = 4(4 1/2)² - 40(4 1/2) + 99
y = 4(20 1/4) - 180 + 99
y = 81 - 180 + 99
y = -99 + 99
y = 0
(x, y) = (4 1/2, 0)
y-intercept
y = 4x² - 40x + 99
y = 4(0)² - 40(0) + 99
y = 4(0) - 0 + 99
y = 0 - 0 + 99
y = 0 + 99
y = 99
(x, y) = (0, 99)
--------------------------------------------------------------------------------------------
vertex
y = (x - 1)² = 2
y = (x - 1)² - 2
y = ((x - 1)(x - 1)) - 2
y = (x² - x - x + 1) - 2
y = x² - 2x + 1 - 2
y = x² - 2x - 1
x² - 2x - 1 = 0
x = -(-2) +/- √((-2)² - 4(1)(-1))
 2(1)
x = 2 +/- √(4 + 4)
 2
x = 2 +/- √(8)
 2
x = 2 +/- 2.83
 2
x = 1 +/- 1.415
x = 1 + 1.415 x = 1 - 1.415
x = 2.415 x = 0.415
y = x² - 2x - 1
y = (2.145)² - 2(2.145) - 1
y = 4.60125 - 4.029 - 1
y = 0.57225 - 1
y = 0.42775
(x, y) = (2.415, 0.42775)
or
y = x² - 2x - 1
y = (0.415)² - 2(0.415) - 1
y = 0.172225 - 0.83 - 1
y = -0.657775 - 1
y = -1.657775
(x, y) = (0.415, -1.657775)
y-intercept
y = x² - 2x - 1
y = (0)² - 2(0) - 1
y = 0 - 0 - 1
y = 0 - 1
y = -1
(x, y) = (0, -1)

6 0

3 years ago

Solve 2x+y=7 for y what is y ?

masha68 [24]

You cant solve y but you can form an equation in terms of y
which is y=7-2x

if you were given another equation that has the term y and x than you can solve it.also that is a simultaneous equation.

Hope this helps,dont forget to put this as the brainliest answer if it does to help me out too. xD

6 0

3 years ago

Read 2 more answers

A dog that weighs 15 pounds should eat 2 1/8 cups of a certain type of dog food per day. How much of the same type of dog food s

cupoosta [38]

If a 15 lbs dog eats................................17/8 cups of food
a 34 lbs dog will eat,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,? cups

(34 * 17/8)/15=(34*17)/(15*8)=289/15= 19 4/15 cups of food

7 0

3 years ago

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

5 0

3 years ago

Five workers dig a trench 5 yards long in 5 hours. How many workers are needed to dig a 100 yards long in 100 hours?

Pavlova-9 [17]

I think it would require 100 workers since 1 worker digs up 1 yard.

Hope this helps.

7 0

3 years ago