3 years ago

Can somebody help with this question

Mathematics

1 answer:

satela [25.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

Parallel lines have same slope.

Slope of the required line = 3/4

(-1,7)

Point slope form: y - y1 = m(x -x1)

$y - 7=\dfrac{3}{4}(x -[-1])\\\\\\y -7 =\dfrac{3}{4}(x+1)$

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If the tangent line to y = f(x) at (7, 4) passes through the point (0, 3), find f(7) and f '(7).

jarptica [38.1K]

Hello :
f'(7) = the slope of the tangent line : let A(7,4) B(0,3)
the slope is : (YB - YA)/(XB -XA)= (3-4)/(0-7) = -1/-7 = 1/7=f'(7)
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3 years ago

Can somebody help with this question ​

Can somebody help with this question