Answer:
35.1 units
Step-by-step explanation:
Imagine a right-angled triangle with RS as hypotenuse. The base would be 3 units and the height would be 6 units. By Pythagorus:
RS²=3²+6²
RS=
≈6.7 units
Imagine a right-angled triangle with RT as hypotenuse. The base would be 9 units and the height would be 12 units. By Pythagorus:
RT²=9²+12²
RT=
= 15 units
Imagine a right-angled triangle with TS as hypotenuse. The base would be 12 units and the height would be 6 units. By Pythagorus:
TS²=12²+6²
TS=
≈13.4 units
Perimeter=RS+RT+TS
=6.7+15+13.4
=35.1 units
I think it would be 12.207… use the Pythagorean theorem (a^2+b^2=c^2) so 10^2+7^2
100+49=149
Then take square root of 149 to undo the the squaring of c and it should be around 12.207 :)
Answer: -5
Step-by-step explanation:
Answer:
Step-by-step explanation:
In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).
The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.
Evaluating the integral gives use that it is equal to;
Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.
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Answer:
2
Step-by-step explanation:
