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juin [17]
2 years ago
8

Can somebody help with this question ​

Mathematics
1 answer:
satela [25.4K]2 years ago
3 0

Answer:

Step-by-step explanation:

Parallel lines have same slope.

Slope of the required line = 3/4

(-1,7)

Point slope form: y - y1 = m(x -x1)

y - 7=\dfrac{3}{4}(x -[-1])\\\\\\y -7 =\dfrac{3}{4}(x+1)

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5) 90°<br> A) acute<br> C) straight<br> B) obtuse<br> D) right
Reil [10]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

A right angle is exactly 90 degrees.

Thus, your answer is option D

Have A Nice Day ❤    

Stay Brainly! ヅ    

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。☆✼★ ━━━━━━━━━━━━━━  ☾

7 0
3 years ago
Read 2 more answers
Help me please in number 4
Dvinal [7]
Larger negative numbers are less than, if you picture a number line.

<.......-83 ............-38........0........+38..........>

-83 < -38

The canyon is deeper or has a lower elevation than the scuba diving location.
5 0
2 years ago
In the diagram above​
Reil [10]

Answer:

<h2>40°</h2>

Step-by-step explanation:

We have parallel lines.

Angles 1 and 2 are alternate angles.

With parallel lines, alternate angles are congruent.

Therefore

m\angle1=m\angle2

m\angle1=2x+20,\ m\angle2=3x+10\\\\2x+20=3x+10\qquad\text{subtract 20 from both sides}\\\\2x+20-20=3x+10-20\\\\2x=3x-10\qquad\text{subtract}\ 3x\ \text{from both sides}\\\\2x-3x=3x-3x-10\\\\-x=-10\qquad\text{change the signs}\\\\x=10\\\\m\angle1=2(10)+20=20+20=40

4 0
3 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy
Debora [2.8K]

Answer:

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

df=n-1=28-1=27  

p_v =P(t_{(27)}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=60 represent the sample mean

s=8.9 represent the sample standard deviation

n=28 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:  

Null hypothesis:\mu \geq 63  

Alternative hypothesis:\mu < 63  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=28-1=27  

Since is a one side lower test the p value would be:  

p_v =P(t_{(27)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

5 0
3 years ago
Factor the expression 15x^2-16xy+4y^2
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(5x-2y)(3x-2y)


Dont give me anything give it to the other lad down there


6 0
3 years ago
Read 2 more answers
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