In the standard form of the equation
![\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%5C%20f%28t%29%3DAcos%5Bb%28t%5Cpm%20c%29%5D%2Bk%5C%5C%20%5C%5C%20)
The middle line =k
For our given problem
f(t) = 40cos (80t + 20)
On comparison we get k=0
Hence middle line=0
Ok so basically you have to anahajahabdbnxnxkskalakand
1. The intersection between plane A and line n is the point x
2. Since the right angle is bisected, the two smaller angles produced have measures of 45 degrees.
<span>c. m∠CEB = 45°
3. There is only 1 line that can be drawn between J and K</span><span />
3) 0.825
4) 0.1212
5) 0.5455
6) -7.177
7a) 0.066
b) 0.166
c) 0.333
d) 0.416
8) -2/5
9) -7 (32/100) = -7 (9/25)
10) 0.22222 = 2/9
