(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
i think its f But im not sure just try doing it because i dont understand it that well
(0,12)
(5,15)
(-20,0)
(30,30)
Easy
sub since boht equal y, both are equal
6x+4=y=4x-2
6x+4=4x-2
minus 4x
2x+4=-2
minus 4
2x=-6
divide 2
x=-3
sub back
y=4x-2
y=4(-3)-2
y=-12-2
y=-14
solution in (x,y) form is
(-3,-14)