Answer:
or reactions that are not at equilibrium, we can write a similar expression called the reaction quotient QQQ, which is equal to K_\text cK
c
K, start subscript, start text, c, end text, end subscript at equilibrium.
Explanation:
Answer:
C. It decreases by a factor of 4
Explanation:
F1 = kq1*q2/r²
F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4) = F1/4
Watt stands for power that is energy per unit time
Answer:
A) 100 mL
Explanation:
At constant temperature and number of moles, Using Boyle's law
Given ,
V₁ = 200 mL
V₂ = ?
P₁ = 60 kPa
P₂ = 120 kPa
Using above equation as:
