How many grams of salt are in 5 L of a solution with a concentration of 3 g/L
1 answer:
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The reaction of 1-bromo-2-methylpropane (isobutyl bromide), , with
, and
results in the formation of an adduct of formula
known as grignard reagent, an organometallic reagent, which on reacting with
results in the formation of isobutane.
The reaction is shown in the image.
Answer: The correct option is 4.
Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:
1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.
2) Beta-minus decay: It is a decay in which a beta particle is released. The beta particle released has a mass number of 0 and a charge of (-1).
3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.
For the given options:
Option 1: This nuclei will undergo beta-plus decay process to form
Option 2: This nuclei will undergo beta-minus decay process to form
Option 3: This nuclei will undergo a beta minus decay process to form
Option 4: This nuclei will undergo an alpha decay process to form
Hence, the correct option is 4.