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Soloha48 [4]
3 years ago
12

Which of the following has electrons in a d orbital? Mg Si Cr Са

Chemistry
1 answer:
erica [24]3 years ago
6 0
Cr.
Cr is the only element listed that is located in the d-block of the periodic table.
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The primary products of complete combustion of fossil fuels are _____.
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Which landform is located at the mouth of the river?
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Landforms. At the mouth of a river, the change in flow condition can cause the river to drop any sediment it is carrying. This sediment deposition can generate a variety of landforms, such as deltas, sand bars, spits, and tie channels.

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4 years ago
A student decomposed 3.67g of copper (ii) hydroxide into copper (ii) oxide. how many ml of 3m h2so4 is need to react with all th
vredina [299]
In the presence of heat, copper (II) hydroxide decomposes in to copper (II) oxide. 
Cu(OH)₂ (s) ----> CuO (s) + H₂O (l)
upon decomposition, water is removed from Cu(OH)₂
the amount of Cu(OH)₂ decomposed - 3.67 g
number of moles of Cu(OH)₂  - 3.67 g / 97.5 g/mol = 0.038 mol
stoichiometry of Cu(OH)₂ to CuO is 1:1
therefore number of CuO moles formed are - 0.038 mol
CuO reacts with sulfuric acid to form CuSO₄ 
CuO + H₂SO₄ ---> CuSO₄ + H₂O
stoichiometry of CuO to H₂SO₄ is 1:1
therefore number of H₂SO₄ moles that should react is 0.038 mol
the molarity of H₂SO₄ is 3M
this means that in 1000 ml - 3 mol of H₂SO₄ present 
so if 3 mol are present in 1000 ml 
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6 0
4 years ago
What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v
ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is \lambda.

Formula to calculate thickness of a benzene thin film is as follows.

     Optical path length through benzene (\lambda) = 2 \times n \times d

Hence, substituting the given values into the above formula as follows.

    Optical path length through benzene = 2 \times n \times d

                   d = \frac{\text{Optical path length through benzene}}{2 \times n}

                       = \frac{\lambda}{2 \times n}  

                       = \frac{615 \times 10^{-9}}{2 \times 1.501}   (as 1 nm = 10^{-9}m

                       = 204.9 m          

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0
3 years ago
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