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3 years ago

Synthetic reactions in Citric Acid Cycle

1 answer:

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★ « Synthetic reactions in Citric Acid Cycle » ★

The overall reaction for the citric acid cycle is as follows: acetyl-CoA + 3 NAD+ + FAD + GDP + P + 2H2O = CoA-SH + 3NADH + FADH2 + 3H+ + GTP + 2CO2.

Many molecules in the citric acid cycle serve as key precursors for other molecules needed by cells.

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When HCl(g) reacts with O2(g) to form H2O(g) and Cl2(g), 6.84 kcal of energy are evolved for each mole of HCl(g) that reacts. Wr

puteri [66]

Answer:

4HCl(g)+O2(g)= 2H2O(g)+2Cl2(g)

∆H=-27.36 kcal

Explanation:

The balanced equation shows that four molecules of HCl reacts with one molecule of Oxygen to give two molecules of water and two molecules of chlorine gas and evolves energy in a combustion reaction.

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3 years ago

The

Georgia [21]

Answer:

Elements

Explanation:

The elements which are represented by a single uppercase letter, or represented by an uppercase letter followed by a lowercase letter. This tells you the types of elements in the compound.

Elements are one of the simplest chemical substances that cannot be decomposed in a chemical reaction or by any chemical means. They are made up of small indivisible particles called atoms, all having the same number of protons.

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3 years ago

Which of these elements in group 1A has the largest atomic radius? Cesium, Rubidium, Potassium, or Sodium?

Savatey [412]

Cesium is the element in group 1A that has the largest atomic radius, with the number of 225.
Rubidium has 211, Potassium 196, and Sodium 154.

8 0

4 years ago

Read 2 more answers

SO2 + 2NaOH → Na2SO3 + H2O

katen-ka-za [31]

Answer:

There will be produced 157.55 grams of Na2SO3. The limiting reactant is NaOH. SO2 is in excess, there will remain 19.9 grams of SO2.

Explanation:

Step 1: Data given

Mass of SO2 = 100 grams

Mass of NaOH = 100 grams

Molar mass of SO2 = 64.07 g/mol

Molar mass of NaOH = 40 g/mol

Molar mass of Na2SO3 = 126.04 g/mol

Step 2: The balanced equation

SO2 + 2NaOH → Na2SO3 + H2O

Step 3: Calculate moles SO2

Moles SO2 = mass SO2 / molar mass SO2

Moles SO2 = 100.0 grams / 64.07 g/mol

Moles SO2 = 1.561 grams

Step 4: Calculate moles of NaOH

Moles NaOH = 100.0 grams / 40 g/mol

Moles NaOH = 2.5 moles

Step 5: Calculate limiting reactant

For 1 mol of SO2 we need 2 moles of NaOH to produce 1 mol Na2SO3 and 1 mol of H2O

NaOH is the limiting reactant. It will completely be consumed.(2.5 moles).

SO2 is in excess. There will be consumed 2.5 / 2 = 1.25 moles of SO2

There will remain 1.561 - 1.25 = 0.311 moles of SO2. This is 0.311 * 64.07 g/mol = 19.9 grams

Step 6: Calculate moles of Na2SO3

There will be produced 1.25 moles of Na2SO3

Step 7: Calculate mass of Na2SO3

Mass Na2SO3 = 1.25 * 126.04 g/mol

Mass Na2SO3 = 157.55 grams

There will be produced 157.55 grams of Na2SO3. The limiting reactant is NaOH. SO2 is in excess, there will remain 19.9 grams of SO2.

6 0

4 years ago

what are the mole ratios of hydrazine (n2h4) to hydrogen peroxide (h2o2) and hydrazine to water? 1:2 and 1:4 1:3 and 1:4 1:2 and

Shalnov [3]

To determine the mole ratios of the substances, we need to know the balanced chemical reaction of the system. The reaction between hydrazine and hydrogen peroxide yields to nitrogen and water. The balanced chemical reaction is:

N2H4 + 2H2O2 --> N2 + 4H2O

Therefore, the mole ratio between hydrazine and hydrogen peroxide is 1:2 and the mole ratio between hydrazine and water is 1:4.

3 0

3 years ago