Answer:
81.85% of the workers spend between 50 and 110 commuting to work
Step-by-step explanation:
We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.
We call X the time spend from one worker; X has distribution N(μ = 70, σ = 20). In order to make computations, we take W, the standarization of X, whose distribution is N(0,1)

The values of the cummulative distribution function of the standard normal, which we denote
, are tabulated. You can find those values in the attached file.

Using the symmetry of the Normal density function, we have that
. Hece,

The probability for a worker to spend that time commuting is 0.8185. We conclude that 81.85% of the workers spend between 50 and 110 commuting to work.
(14.80)(5) = 74
6-5 = 1
(17)(1) = 17
74 + 17 = 91
5 family members orders chicken, and only one orders steak.
The expected value is the sum of values multiplied by their probabilities.
... 15×(1/5+1/5) + 5×(3/5) = 6+3 = 9
The expected value of a single spin is 9 points.
Answer:
The answer is: y = 3x - 7
Step-by-step explanation:
Given point: (5, 8).
Slope m = 3
Use the point slope form and solve for y:
y - y1 = m(x - x1)
y - 8 = 3(x - 5)
y - 8 = 3x - 15
y = 3x - 15 + 8
y = 3x - 7
Proof:
f(x) = 3x - 7
f(5) = 3(5) - 7
= 15 - 7 = 8, giving (5, 8)