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2 years ago

Express each number in scientific notation.

Mathematics

1 answer:

Alchen [17]2 years ago

7 0

Answer:

1.3 x 10^6

8.825 x 10^8

1.25 x 10^4

5.167 x 10^7

Step-by-step explanation:

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Determine which point is part of the solution set to the following

umka21 [38]

I think 4,6
I had a test similar I’m not the best at it though hope this helps tho

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2 years ago

Let f(x) = 7^x and g(x) = 7^x+2 - 4 which transformations are needed to strand form the graph of f(x) to the graph of g(x)?

serg [7]

Answer:

options 3 and 6

Step-by-step explanation:

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2 years ago

Please provide the answer?

Brums [2.3K]

Using the given table:

a) the average rate of change is 32.5 jobs/year.

b) the average rate of change is 12.5 jobs/year.

<h3>How to find the average rate of change?</h3>

For a function f(x), the average rate of change on an interval [a, b] is:

$\frac{f(b) - f(a)}{b - a}$

a) The average rate of change between 1997 and 1999 is:

$A = \frac{695 - 630}{1999 - 1997} = 32.5$

So the average rate of change is 32.5 jobs/year.

b) Now the interval is 1999 to 2001.

The rate this time is:

$A ' = \frac{720 - 695}{2001 - 1999} = 12.5$

So the average rate of change is 12.5 jobs/year.

If you want to learn more about average rates of change:

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1 year ago

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

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2 years ago

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Kate needs to swim 40 laps to come complete 66 laps

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