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Mila [183]
2 years ago
5

Given ∆TOM with vertices T(-1, 8), O(-3, 3), and M(-6, 7). (a) Graph ∆TOM on the axes provided below. (Draw it in your notes) (b

) On the same set of axes, graph ∆T'O'M', the image of ∆TOM reflected over the line y = -x. (c) On the same set of axes, graph ∆T"O"M", the image of ∆T'O'M' reflected over the x-axis.
Mathematics
1 answer:
gogolik [260]2 years ago
8 0

Answer:

i dont know if i did this right buut

Step-by-step explanation:

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Yup it has to be a greater divedend if not answer would be completly  wrong
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3 years ago
(2545.24 x 4242.06) + 2/100=
Vinvika [58]
Answer : <span>10797060.8144

</span>2545.24 x 4242.06 = <span>10797060.7944

</span>10797060.7944 + 2/100 = 10797060.8144
5 0
3 years ago
Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0
3 years ago
An angle in a triangle measures 138 °. The other two angles are congruent. Enter and solve an equation to find the x measure of
Juli2301 [7.4K]

Hey there! I"m happy to help!

The interior angles of a triangle add up to 180. We have 2 angles that have a value of x, so 2x+138=180.

We subtract 138 from both sides.

2x=42

We divide both sides by 2

x=21.

Have a wonderful day! :D

5 0
3 years ago
the pizza slice served at O'Connor's pizza place are 1/4 of a whole pizza. There are three pizzas ready to be served. 14 childre
likoan [24]
No there will not be enough. Think about it this way. If each slice is 1/4 of the pizza, then each pizza can only feed 4 people. If you have 3 of these pizzas, then you can feed 12 people at most. Since there are 14 kids, you won't have enough.
8 0
3 years ago
Read 2 more answers
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