<u>Answer:</u> The volume of hydrogen gas required for the given amount of ethylene gas is 113 L
<u>Explanation:</u>
At STP:
1 mole of a gas occupies 22.4 L of volume
We are given:
Volume of ethylene = 113 L
For the given chemical equation:
By Stoichiometry of the reaction:
of ethylene reacts with of hydrogen gas
So, 113 L of ethylene gas will react with = 
of hydrogen gas
Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L
Answer:
The answer to your question is below
Explanation:
Data
Test tube 1 Test tube 2
Magnesium + Sulfuric acid Magnesium + Acetic acid
Mg + H₂SO₄ Mg + CH₃COOH
a) Test tube 1 will have a more vigorous reaction than test tube 2.
b) Sulfuric acid is a strong acid and Acetic acid is a weak acid.
c)
i.- Sulfuric acid because is a strong acid
ii.- Acetic acid because is a weak acid.
Answer:
19
Explanation:
Once you add all the weights together, you end up with 114 then you divide it by how many dogs there are, 6. 114/6 = 19. The average is 19 lbs.
Plasma Membrane, nucleus, and cytoplasm
Global warming, Cosmic Background radiation (even though most is blocked not ALL), and pollution.
