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djyliett [7]
2 years ago
6

Which of these is an acid?

Chemistry
2 answers:
dolphi86 [110]2 years ago
6 0

Answer:

3) Vinegar

Step-by-step explanation:

Vinegar is a dilute solution of acetic acid. It has a<em> sour tast</em>e and <em>turns blue litmus red</em>.

1)  NaOH and 3) lye are <em>bases</em>. They both have a slippery feel and turn red litmus blue.

2) Water is <em>neutral</em>. It is neither an acid nor a base.

dmitriy555 [2]2 years ago
5 0
Vinegar is the only one that is an acid
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Your job is to determine the concentration of ammonia in a commercial window cleaner. In the titration of a 25.0 mL sample of th
ruslelena [56]

Answer:

The initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      .....(1)

Molarity of HCl solution = 0.164 M

Volume of solution = 23.8 mL = 0.0238 L    (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

0.164M=\frac{\text{Moles of HCl}}{0.0238L}\\\\\text{Moles of HCl}=(0.146mol/L\times 0.0238L)=0.0035mol

The chemical equation for the reaction of ammonia and HCl follows:

NH_3+HCl\rightarrow NH_4^++Cl^-

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of ammonia

So, 0.0035 moles of HCl will react with = \frac{1}{1}\times 0.0035=0.0035mol of ammonia

  • Calculating the initial concentration of ammonia by using equation 1:

Moles of ammonia = 0.0035 moles

Volume of solution = 25 mL = 0.025 L

Putting values in equation 1, we get:

\text{Initial concentration of ammonia}=\frac{0.0035mol}{0.025L}=0.14M

By Stoichiometry of the reaction:

1 mole of ammonia produces 1 mole of ammonium ion

So, 0.0035 moles of ammonia will react with = \frac{1}{1}\times 0.0035=0.0035mol of ammonium ion

  • Calculating the concentration of ammonium ion by using equation 1:

Moles of ammonium ion = 0.0035 moles

Volume of solution = [23.8 + 25] mL = 48.8 mL = 0.0488 L

Putting values in equation 1, we get:

\text{Molarity of ammonium ion}=\frac{0.0035mol}{0.0488L}=0.072M

  • To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

K_w=K_b\times K_a

where,

K_w = Ionic product of water = 10^{-14}

K_a = Acid dissociation constant

K_b = Base dissociation constant = 1.8\times 10^{-5}

10^{-14}=1.8\times 10^{-5}\times K_a\\\\K_a=\frac{10^{-14}}{1.8\times 10^{-5}}=5.55\times 10^{-10}

The chemical equation for the dissociation of ammonium ion follows:

NH_4^+\rightarrow NH_3+H^+

The expression of K_a for above equation follows:

K_a=\frac{[NH_3][H^+]}{[NH_4^+]}

We know that:

[NH_3]=[H^+]=x

[NH_4^+]=0.072M

Putting values in above expression, we get:

5.55\times 10^{-10}=\frac{x\times x}{0.072}\\\\x=6.32\times 10^{-6}M

To calculate the pH concentration, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=6.32\times 10^{--6}M

pH=-\log (6.32\times 10^{-6})\\\\pH=5.20

Hence, the initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

5 0
2 years ago
At a particular temperature and [A]0 = 2.00 x 10-2 Molar, concentration versus time data were collected for this reaction and a
madreJ [45]
<h2>Answer:kllk<em>klkkkk</em></h2>

Explanation:

4 0
3 years ago
1 Condensation
larisa86 [58]

Answer:

Explanation:

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B ) Evaporation

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2 years ago
The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10
Ugo [173]

Answer:

The correct option is a.

Explanation:

2N_2O_5\rightarrow 4NO_2 + O_2

125 kPa

125kpa - 2x                            4x    x

Total pressure after reaction = 176 kPa

125 kPa - 2x + 4x + x = 176 kPa

x = 17

125 kpa - 2x = 125 kPa - 2(17) = 91 kPa

Initial pressure of the dinitrogen pentoxide ,(at t=0) =P_o= 125 kPa

Final pressure of the dinitrogen pentoxide, (at t = t) = P = 91 kPa

The rate constant is = k = 2.8\times 10^{-3} min^{-1}

t=\frac{2.303}{k}\log\frac{P_o}{P}

t=\frac{2.303}{2.8\times 10^{-3} min^{-1}}\log\frac{125 kPa}{91 kPa}

t=113.3969 minutes\approx 113 minutes

It will take 113 minutes for the total pressure to reach 176 kPa.

8 0
2 years ago
According to current theory, a major reason for bonding is
tatiyna
Covalent bond   a chemical bond formed by two electrons that are shared between two atoms
ionic bond<span>    a chemical bond formed by the electrostatic attraction between ions</span>
metallic bond<span>    a bond characteristic of metals in which mobile valence electrons are shared among positive nuclei in the metallic crystal</span>
6 0
2 years ago
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