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MArishka [77]
2 years ago
6

A certain mass of sugar can be divided into equal heaps. Each heap contains either 27g, 45g, 30g, or 20g. Find the smallest mass

of sugar for which is possible
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
7 0

The smallest mass of sugar for which that will be possible will be <u>30.5g.</u>

Since we're given the information that each heap contains either 27g, 45g, 30g, or 20g, then in order to calculate the smallest mass of sugar that can be divided to get equal heaps, we've to find the average of the numbers given and this will be:

= (27g + 45g + 30g + 20g) / 4

= 122g / 4

= 30.5g

In conclusion, the correct option is 30.5g.

Read related link on:

brainly.com/question/25135673

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Select all the pairs of equivalent expressions.
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Answer:

\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}

Step-by-step explanation:

a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================

(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================

6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================

4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3

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Step-by-step explanation:

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