Answer:
7.06 x 10^(-7) ft 3
Step-by-step explanation:
We have the formula to calculate the volume of an octagonal Pyraamid as following:
<em>+) Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
As given, the base of the pyramid is an octagon with area equal to 15mm2
=> Area of the base = 15 mm2
The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.
=> Height = 4mm
So we have:
<em>Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
<em>= 1/3 * 15 * 4 = 20 mm3</em>
<em />
As: 1 mm3 = 3.53 x 10^(-8) ft 3
=> 20 mm3 = 7.06x10^(-7) ft 3
So the volume of the pyramid is : 7.06 x 10^(-7) ft 3
The ratio 4 to 7. would be 12 and 21
For midsegment theorem
And parallels lune are twice
So AB = YZ /2
AB = 10/2 =5
BUT AB = X–1 =5
X–1 = 5 = X = 1+5 =6
X =;6
..
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Step-by-step explanation:
1.6a= -9.12
a= -9.12/1.6
=−5.7
option B
