Predict how many antacid tablets it would take to produce 120 mL of CO2 gas

What is the first step in creating a unit conversion factor?

NNADVOKAT [17]

Determining the units.

5 0

3 years ago

Arrange carbon, phosphorus and sulfur in order of reactivity to write their reaction with oxygen.

mihalych1998 [28]

Answer:

Solid phosphorus reacts with gaseous oxygen to produce solid diphosphorus pentaoxide. ... Methanol burns in oxygen to produce carbon dioxide gas and water vapor.

Explanation:

Solid phosphorus reacts with gaseous oxygen to produce solid diphosphorus pentaoxide. ... Methanol burns in oxygen to produce carbon dioxide gas and water vapor.

6 0

2 years ago

Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d

worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+B\rightarrow Products$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b$

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

$3.20\times 10^{-1}=k(1.50)^a(1.50)^b$ ....(1)

Expression for rate law for second observation:

$3.20\times 10^{-1}=k(1.50)^a(2.50)^b$ ....(2)

Expression for rate law for third observation:

$6.40\times 10^{-1}=k(3.00)^a(1.50)^b$ ....(3)

Dividing 1 from 2, we get:

$\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0$

Dividing 1 from 3, we get:

$\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1$

Thus, the rate law becomes:

$\text{Rate}=k[A]^1[B]^0$

$\text{Rate}=k[A]$

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0

3 years ago

A cyanide solution with avolume of 12.73 mL was treated with 25.00 mL of Ni2+solution (containing

natima [27]

Answer:

The molarity of this solution is 0,09254M

Explanation:

The concentration of the Ni²⁺ solution is:

Ni²⁺ + EDTA⁴⁻ → Ni(EDTA)²⁻

0,03935L × 0,01307M = 5,143x10⁻⁴ moles Ni²⁺ ÷ 0,03010L =0,01709M Ni²⁺

25,00 mL of this solution contain:

0,01709M × 0,02500L = 4,2716x10⁻⁴ moles of Ni²⁺

The moles of Ni²⁺ that are in excess and react with EDTA⁴⁻ are:

0,01015L × 0,01307M = 1,3266x10⁻⁴ moles of Ni²⁺

Thus, moles of Ni²⁺ that react with CN⁻ are:

4,2716x10⁻⁴ - 1,3266x10⁻⁴ = 2,9450x10⁻⁴ moles of Ni²⁺

For the reaction:

4CN⁻ + Ni²⁺ → Ni(CN)₄²⁻

Four moles of CN⁻ react with 1 mole of Ni²⁺:

2,9450x10⁻⁴ moles of Ni²⁺ × $\frac{4 mol CN^-}{1 molNi^{2+}}$ = 1,178x10⁻³ moles of CN⁻

As the volume of cyanide solution is 12,73mL. The molarity of this solution is:

1,178x10⁻³ moles of CN⁻ ÷ 0,01273L = 0,09254M

I hope it helps!

5 0

3 years ago

7. A 26.4-ml sample of ethylene gas, C2H4, has a pres-sure of 2.50 atm at 2.5°C. If the

never [62]

Answer: 1.87 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 2.50 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 26.4 ml

$V_2$ = final volume of gas = 36.2 ml

$T_1$ = initial temperature of gas = $2.5^oC=273+2.5=275.5K$

$T_2$ = final temperature of gas = $10^oC=273+10=283K$

Now put all the given values in the above equation, we get:

$\frac{2.50\times 26.4}{275.5}=\frac{P_2\times 36.2}{283}$

$P_2=1.87atm$

The new pressure is 1.87 atm by using combined gas law.

6 0

3 years ago