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gogolik [260]
3 years ago
5

I need help with this

Chemistry
1 answer:
masha68 [24]3 years ago
6 0
Answer is —-7373/63)3
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Give three examples,from the lab where potential energy was converted to kinetic energy?​
creativ13 [48]

Answer:

*a car geared neutral that is at a stop. two men start pushing it

*tire physical therapy. trie is at rest until you come up to the tire and flip it

*pushing a wheel barrel  

Explanation:

everthing has to be at a complete stop then through energy be moved

7 0
4 years ago
Describe how to do an experiment to show that when you dissolve salt in water the salt is still there.
Alex17521 [72]

Answer:

When salt is dissolved in water, the particles of salt get into the spaces between particles of water and starts dissolving and disappear.

Explanation:

8 0
3 years ago
A mixture containing initially 3.90 mole of NO(g) and 0.88 mole of CO2(g) was allowed to react in a flask of volume 1.00 L at a
Ymorist [56]

Answer:

Equilibrium constant Kc for the reaction will be 1.722

Explanation:

O2(g)+NO(g)→CO(g)+ NO2(g)

0.88    3.9        ---         ---

0.88x   3.9-x     x           x

GIVEN:

0.88X-X= 0.11

⇒ X=0.77

CO2(g)+NO(g) → CO(g) + NO2(g)

0.88       3.9         ---          ---

0.88-x    3.9-x      x            x

=              3.13       0.77      0.77

=0.11

Kc = \frac{[CO] *[NO2]} {[CO2]*[NO]}

     ={{0.77}×0.77÷{{0.11×3.13}}

     = 1.722

6 0
3 years ago
What is the general form of a decomposition reaction
likoan [24]

A reaction where one becomes two


2H202 --> 2H2O + O2

8 0
3 years ago
Given: logK=nE∘0.0592 What is the value K for this redox reaction? Zn2+(aq) + 2 Cl−(aq) → Zn(s) + Cl2(
anygoal [31]

<em>K</em> = 2.4 × 10^(-72)

<em>Step 1</em>. Determine the <em>value of n </em>

Zn^(2+) + 2e^(-) → Zn

2Cl^(-) → Cl_2 + 2e^(-)

Zn^(2+) + 2Cl^(-) → Zn + Cl_2

∴ <em>n</em> = 2

<em>Step 2</em>. Calculate <em>K</em>

log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62

<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)

8 0
4 years ago
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