Answer:
The pressure inside the container is 6.7 atm
Explanation:
We have the ideal gas equation: P x V = n x R x T
whereas, P (pressure, atm), V (volume, L), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)
Since the container is evacuated and then sealed, the volume of the body of gas is the volume of the container.
So we can calculate the pressure by
P = n x R x T / V
where as,
n = 41.1 g / 44 g/mol = 0.934 mol
Hence P = 0.934 x 0.082 x 298 / 3.4 L = 6.7 atm
A general equation for a combustion reaction would be expressed as follows:
CxHy + (x+y/2)O2 = xCO2 + y/2H2O
Propane would obviously would only have carbon and hydrogen in its structure. Assuming a complete combustion, all of the carbon atoms would go to carbon dioxide and all of the hydrogen atoms to water. To determine the empirical, we determine the number of carbon and hydrogen atoms present.
moles C = 2.461 g CO2 ( 1 mol / 44.01 g ) ( 1 mol C / 1 mol CO2 ) = 0.06 mol C
moles H = 1.442 g H2O ( 1 mol / 18.02 g ) ( 2 mol H / 1 mol H ) = 0.16 mol H
Then, we divide the smallest amount to the each mole of the atoms. We do as follows:
C = 0.06 / 0.06 = 1
H = 0.16 / 0.06 = 2.67
Then we multiply a number in order to obtain a whole number ratio between the atoms.
1 CH2.67
2 C2H5.34
3 C3H8 <-------- empirical formula
The chemical makeup found on the periodic table.
