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boyakko [2]
3 years ago
11

Terrence would like to estimate the mean the number of books students at his school read during the summer. There are 595 studen

ts at his school.
Which statements are true?

Select each correct answer.

Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0
To estimate mean using a sample. Terrance will need to randomly select students he will survey so that the sample represents the population well

Umnica [9.8K]3 years ago
4 0

Answer:

As, there are 595 students in the school.

To find the mean number of books, read by student in the school during summer

If he will survey all the students in the school that will give the exact mean , but that will be little lengthy and tedious.

As, well as larger the number of students surveyed , the better the mean is.

But option A, is true as, select randomly few students , find the mean number of books read by them , that will be less time consuming and gives the mean of population also.

Option A:

To estimate the mean using sample,Terrance will need to randomly select students, he will survey and that represents population as well.

Apart from option A,option B is also true.

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Step-by-step explanation:

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Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.
lakkis [162]

Answer:

2*sin(x)+y*cos(x)-cos(y)=C_1

Step-by-step explanation:

Let:

P(x,y)=2*cos(x)-y*sin(x)

Q(x,y)=cos(x)+sin(y)

This is an exact differential equation because:

\frac{\partial P(x,y)}{\partial y} =-sin(x)

\frac{\partial Q(x,y)}{\partial x}=-sin(x)

With this in mind let's define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x}=P(x,y)

and

\frac{\partial f(x,y)}{\partial y}=Q(x,y)

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y)

f(x,y)=\int\  2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}

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cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)

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\frac{dg(y)}{dy}=sin(y)

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g(y)=\int\ sin(y)  \, dy =-cos(y)

Replacing this result into f(x,y)

f(x,y)=2*sin(x)+y*cos(x)-cos(y)

Finally the solution is f(x,y)=C1 :

2*sin(x)+y*cos(x)-cos(y)=C_1

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Step-by-step explanation:

3 0
3 years ago
Uh can someone please help? please get it right and try to explain how
Anestetic [448]

Answer:

From least likely to most likely:

Colorado Bronze wins

I Am Pat wins

Good Legs Lance wins

Step-by-step explanation:

Converting all probabilities to the same type may be easier to visualize and see the chances. Let's convert each chance to percentage:

P(I Am Pat wins) = 3/10 = <u>30%</u>

P(Good Legs Lance wins) = 0.6 = <u>60%</u>

P(Colorado Bronze wins) = 10%= <u>10%</u>

Thus, the desired order is:

Colorado Bronze wins

I Am Pat wins

Good Legs Lance wins

4 0
3 years ago
Read 2 more answers
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