Answer:
Originally Answered: How many times does 8 occur in 1 to 100? 20 8's occur from 1 to 100. 8, 18, 28, 38, 48, 58, 68, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89 and 98.
Step-by-step explaintion: i am 5 million iq brainlist pls
Answer:
C: $508.06
Step-by-step explanation:
You read the balance in the "balance" column on the line marked "car payment." It is $508.06.
<h3>
Answer: Largest value is a = 9</h3>
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Work Shown:
b = 5
(2b)^2 = (2*5)^2 = 100
So we want the expression a^2+3b to be less than (2b)^2 = 100
We need to solve a^2 + 3b < 100 which turns into
a^2 + 3b < 100
a^2 + 3(5) < 100
a^2 + 15 < 100
after substituting in b = 5.
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Let's isolate 'a'
a^2 + 15 < 100
a^2 < 100-15
a^2 < 85
a < sqrt(85)
a < 9.2195
'a' is an integer, so we round down to the nearest whole number to get 
So the greatest integer possible for 'a' is a = 9.
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Check:
plug in a = 9 and b = 5
a^2 + 3b < 100
9^2 + 3(5) < 100
81 + 15 < 100
96 < 100 .... true statement
now try a = 10 and b = 5
a^2 + 3b < 100
10^2 + 3(5) < 100
100 + 15 < 100 ... you can probably already see the issue
115 < 100 ... this is false, so a = 10 doesn't work
39/500 needs to be multiplied by 15, which results in 585/500. This is 1.17 as a decimal. 191/200 in diameter needs to be multiplied by 8, which equals 1528/200. This is 7.64 as a decimal.
Answer:
1375
Step-by-step explanation:
25*55= 1375